select in case문 질문

#!/bin/bash
##v.2.0

export IP1="0"
export IP2="0"
export IP3="0"
export DATE=$(date +"%F")
PS3="Select the option "

select char in "1, Check IP" "2, IP List" "3, Exit" #"4"#
do
   case $char in

   1*)  read -p "Enter IP xxx.xxx.xxx. > " -t 20 IP1
        read -p "Enter start IP xxx > " -t 20 IP2
        read -p "Enter last IP xxx > " -t 20  IP3

        echo -e "\033[32;1m"IP Checking!"\033[0m"

        while [[ $IP2 -lt $IP3 ]]; do

        ping -c 1 -w 1 $IP1$IP2 > /dev/null

        if [[ $? == 0 ]]; then
         echo $IP1$IP2 is In-use. >> /tmp/ip_list_$DATE ;
        else
         echo $IP1$IP2 is Dead or Available. >> /tmp/ip_list_$DATE ;
        fi
        IP2=$(($IP2+1))
        done
        echo -e "\033[31;1m"IP Check well done! please verify IP"\033[0m" ;;

   2*)  grep -q  Avail* 2> /dev/null < /tmp/ip_list_$DATE
        if [[ $? == 0 ]]; then
          grep -r --color=always Available /tmp/ip_list_$DATE | sort -u
        else
          echo -e "\033[31;3m"There is no available IP"\033[0m"
        fi  ;;

   3*)  echo "Good bye"; exit 0 ;;

   #4*)  echo "You choose not yet menu it will be add section coming soon asap" ;;
   *)   echo "!!Error select correctly number!!"
   esac


done

[root@hlldvc ddrec]# ./ipcheck.sh
1) 1, Check IP
2) 2, IP List
3) 3, Exit
Select the option