- 학습 관련 질문을 남겨주세요. 상세히 작성하면 더 좋아요! - 먼저 유사한 질문이 있었는지 검색해보세요. - 서로 예의를 지키며 존중하는 문화를 만들어가요. - 잠깐! 인프런 서비스 운영 관련 문의는 1:1 문의하기를 이용해주세요.안녕하세요 선생님 비트마스킹의 어려움 때문에 복습하고 있는데 1~20 까지 수들의 이진수를 외워 두는게 도움이 될까요???

1. ARRAY, STRUCT 연습문제array_exercises 테이블에서 각 영화(title)별로 장르(genres)를 UNNEST해서 보여주세요.SELECT title, genre FROM advanced.array_exercises AS ae CROSS JOIN UNNEST(genres) AS genrearray_exercises 테이블에서 각 영화(title)별로 배우(actor)와 배역(character)을 보여주세요. 배우와 배역은 별도의 컬럼으로 나와야 합니다.SELECT title, actor.actor, actor.character FROM advanced.array_exercises AS ae CROSS JOIN UNNEST(actors) AS actorarray_exercises 테이블에서 각 영화(title)별로 배우(actor)와 배역(character), 장르(genre)를 출력하세요. 한 Row에 배우, 배역, 장르가 모두 표시되어야 합니다.SELECT title, actor.actor, actor.character, genre FROM advanced.array_exercises AS ae , UNNEST(actors) AS actor , UNNEST(genres) AS genre앱 로그 데이터(app_logs)의 배열을 풀어주세요.SELECT user_id, event_date, event_name, user_pseudo_id, event_param.key AS key, event_param.value.string_value AS string_value, event_param.value.int_value AS int_value FROM advanced.app_logs , UNNEST(event_params) AS event_param -- WHERE -- event_date = "2022-08-01"2. PIVOT 연습 문제orders 테이블에서 유저(user_id)별로 주문 금액(amount)의 합계를 PIVOT 해주세요.날짜(order_date)를 행(row)으로, user_id를 열(column)으로 만들어야 합니다.SELECT order_date, MAX(IF(user_id = 1, sum_of_amount, 0)) AS user_1, MAX(IF(user_id = 2, sum_of_amount, 0)) AS user_2, MAX(IF(user_id = 3, sum_of_amount, 0)) AS user_3 FROM ( SELECT order_date, user_id, SUM(amount) AS sum_of_amount FROM advanced.orders GROUP BY order_date, user_id ORDER BY order_date ) GROUP BY order_date ORDER BY order_dateorders 테이블에서 날짜(order_date)별로 유저들의 주문 금액(amount)의 합계를 PIVOT 해주세요.user_id를 행(row)으로, order_date를 열(column)으로 만들어야 합니다.SELECT user_id, MAX(IF(order_date = '2023-05-01', amount, 0)) AS `2023-05-01`, MAX(IF(order_date = '2023-05-02', amount, 0)) AS `2023-05-02`, MAX(IF(order_date = '2023-05-03', amount, 0)) AS `2023-05-03`, MAX(IF(order_date = '2023-05-04', amount, 0)) AS `2023-05-04`, MAX(IF(order_date = '2023-05-05', amount, 0)) AS `2023-05-05`, FROM advanced.orders GROUP BY user_id ORDER BY user_idorders 테이블에서 사용자(user_id)별, 날짜(order_date)별로 주문이 있다면 1, 없다면 0으로 해주세요.user_id를 행(row)으로, order_date를 열(column)로 만들고 주문을 많이 해도 1로 처리합니다.SELECT user_id, MAX(IF(order_date = '2023-05-01', 1, 0)) AS `2023-05-01`, MAX(IF(order_date = '2023-05-02', 1, 0)) AS `2023-05-02`, MAX(IF(order_date = '2023-05-03', 1, 0)) AS `2023-05-03`, MAX(IF(order_date = '2023-05-04', 1, 0)) AS `2023-05-04`, MAX(IF(order_date = '2023-05-05', 1, 0)) AS `2023-05-05`, FROM advanced.orders GROUP BY user_id ORDER BY user_iduser_id = 32888이 카트 추가하기(click_cart)를 누를 때 어떤 음식(food_id)을 담았나요?WITH base AS ( SELECT event_date, event_timestamp, event_name, user_id, user_pseudo_id, MAX(IF(event_param.key = 'firebase screen', event_param.value.string_value, NULL)) AS firebase_screen, MAX(IF(event_param.key = 'food_id', event_param.value.int_value, null)) AS food_id, MAX(IF(event_param.key = 'session_id', event_param.value.string_value, null)) AS session_id FROM advanced.app_logs , UNNEST(event_params) AS event_param GROUP BY ALL ) SELECT food_id FROM base WHERE user_id = 32888 AND event_name = 'click_cart' GROUP BY food_id3. 퍼널 분석 연습문제각 퍼널의 유저 수를 집계WITH base AS( SELECT event_date, event_timestamp, event_name, user_id, user_pseudo_id, platform, MAX(IF(event_param.key = "firebase_screen", event_param.value.string_value, NULL)) AS firebase_screen, MAX(IF(event_param.key = "food_id", event_param.value.int_value, NULL)) AS food_id, MAX(IF(event_param.key = "session_id", event_param.value.int_value, NULL)) AS session_id FROM `advanced.app_logs` CROSS JOIN UNNEST(event_params) AS event_param GROUP BY ALL ), filter_event_and_concat_event_and_screen AS( SELECT * EXCEPT(event_name, firebase_screen), CONCAT(event_name, "-", firebase_screen) AS event_name_with_screen, DATETIME(TIMESTAMP_MICROS(event_timestamp), "Asia/Seoul") AS event_datetime FROM base WHERE event_date BETWEEN "2022-08-01" AND "2022-08-18" AND event_name IN ("screen_view", "click_payment") AND firebase_screen IN ("welcome", "home", "food_category", "restaurant", "cart") ) SELECT event_date, event_name_with_screen, CASE WHEN event_name_with_screen = 'screen_view-welcome' THEN 1 WHEN event_name_with_screen = 'screen_view-home' THEN 2 WHEN event_name_with_screen = 'screen_view-food_category' THEN 3 WHEN event_name_with_screen = 'screen_view-restaurant' THEN 4 WHEN event_name_with_screen = 'screen_view-cart' THEN 5 WHEN event_name_with_screen = 'click_payment-cart' THEN 6 ELSE NULL END AS step_number, COUNT(DISTINCT user_pseudo_id) AS cnt FROM filter_event_and_concat_event_and_screen GROUP BY ALL HAVING step_number IS NOT NULL ORDER BY event_date, step_number

[ARRAY, STRUCT] 문제 1) array_exercises 테이블에서 각 영화(title)별로 장르(genres)를 UNNEST해서 보여주세요.SELECT title, genre FROM advanced.array_exercises CROSS JOIN UNNEST(genres) AS genre쿼리 결과 1)문제 2) array_exercises 테이블에서 각 영화(title)별로 배우(actor)와 배역(character)을 보여주세요.SELECT title, actor.actor, actor.character FROM advanced.array_exercises CROSS JOIN UNNEST(actors) AS actor쿼리 결과 2) 문제 3) array_exercises 테이블에서 각 영화(title)별로 배우(actor), 배역(character), 장르 (genre)를 출력하세요. 한 Row에 배우, 배역, 장르가 모두 표시되어야 합니다.SELECT title, actor.actor AS actor, actor.character AS character, genre FROM advanced.array_exercises CROSS JOIN UNNEST(genres) AS genre CROSS JOIN UNNEST(actors) AS actor쿼리 결과 3)문제 4) 앱 로그 데이터(app_logs) 배열 풀기SELECT event_date, event_timestamp, event_name, event_param.key AS key, event_param.value.string_value AS string_value, event_param.value.int_value AS int_value, user_id, user_pseudo_id, platform FROM `advanced.app_logs` CROSS JOIN UNNEST(event_params) AS event_param WHERE event_date = "2022-08-01" LIMIT 100쿼리 결과 4)[PIVOT]문제 1) orders 테이블에서 유저(user_id)별로 주문 금액(amount)의 합계를 PIVOT해주세요.날짜(order_date)를 행(Row)으로, user_id를 열(Column)으로 만들어야 합니다.SELECT order_date, SUM(IF(user_id = 1, amount, 0)) AS user_1, SUM(IF(user_id = 2, amount, 0)) AS user_2, SUM(IF(user_id = 3, amount, 0)) AS user_3 FROM advanced.orders GROUP BY ALL ORDER BY order_date쿼리 결과 1)문제 2) orders 테이블에서 날짜(order_date)별로 유저들의 주문 금액(amount)의 합계를 PIVOT 해주세요. user_id를 행(Row)으로, order_date를 열(Column)으로 만들어야 합니다SELECT user_id, SUM(IF(order_date = "2023-05-01", amount, 0)) AS `2023-05-01`, SUM(IF(order_date = "2023-05-02", amount, 0)) AS `2023-05-02`, SUM(IF(order_date = "2023-05-03", amount, 0)) AS `2023-05-03`, SUM(IF(order_date = "2023-05-04", amount, 0)) AS `2023-05-04`, SUM(IF(order_date = "2023-05-05", amount, 0)) AS `2023-05-05`, FROM advanced.orders GROUP BY ALL ORDER BY user_id 쿼리 결과 2)문제 3) orders 테이블에서 사용자(user_id)별, 날짜(order_date)별로 주문이 있다면 1, 없다면 0으로 PIVOT 해주세요. user_id를 행(Row)으로, order_date를 열(Column)로 만들고 주문을 많이 해도 1로 처리합니다SELECT user_id, MAX(IF(order_date = "2023-05-01", 1, 0)) AS `2023-05-01`, MAX(IF(order_date = "2023-05-02", 1, 0)) AS `2023-05-02`, MAX(IF(order_date = "2023-05-03", 1, 0)) AS `2023-05-03`, MAX(IF(order_date = "2023-05-04", 1, 0)) AS `2023-05-04`, MAX(IF(order_date = "2023-05-05", 1, 0)) AS `2023-05-05`, FROM advanced.orders GROUP BY ALL ORDER BY user_id 쿼리 결과 3)문제 4)user_id = 32888이 카트 추가하기(click_cart)를 누를때 어떤 음식(food_id)을 담았나요?WITH base AS ( SELECT event_date, event_timestamp, event_name, user_id, user_pseudo_id, MAX(IF(event_param.key = 'firebase_screen',event_param.value.string_value, NULL)) AS firebase_screen, MAX(IF(event_param.key = 'food_id',event_param.value.int_value, NULL)) AS food_id, MAX(IF(event_param.key = 'session_id',event_param.value.string_value, NULL)) AS session_id, FROM advanced.app_logs CROSS JOIN UNNEST(event_params) AS event_param GROUP BY ALL ) SELECT user_id, event_date, COUNT(user_id) AS user_cnt, food_id FROM base WHERE user_id = 32888 and event_name = 'click_cart' GROUP BY ALL쿼리 결과 4) [퍼널분석]WITH base AS ( SELECT event_date, event_timestamp, event_name, user_id, user_pseudo_id, platform, MAX(IF(event_param.key = "firebase_screen", event_param.value.string_value, NULL)) AS firebase_screen, MAX(IF(event_param.key = "session_id", event_param.value.string_value, NULL)) AS session_id FROM advanced.app_logs CROSS JOIN UNNEST(event_params) AS event_param WHERE event_date BETWEEN "2022-08-01" AND "2022-08-18" GROUP BY ALL ), filter_event_and_concat_event_and_screen AS ( SELECT * EXCEPT(event_name, firebase_screen, event_timestamp), CONCAT(event_name, "-", firebase_screen) AS event_name_with_screen, DATETIME(TIMESTAMP_MICROS(event_timestamp), 'Asia/Seoul') AS event_datetime FROM base WHERE event_name IN ("screen_view", "click_payment") ) SELECT event_date, event_name_with_screen, CASE WHEN event_name_with_screen = "screen_view-welcome" THEN 1 WHEN event_name_with_screen = "screen_view-home" THEN 2 WHEN event_name_with_screen = "screen_view-food_category" THEN 3 WHEN event_name_with_screen = "screen_view-restaurant" THEN 4 WHEN event_name_with_screen = "screen_view-cart" THEN 5 WHEN event_name_with_screen = "click_payment-cart" THEN 6 ELSE NULL END AS step_number, COUNT(DISTINCT user_pseudo_id) AS cnt FROM filter_event_and_concat_event_and_screen GROUP BY ALL HAVING step_number IS NOT NULL 쿼리 결과

1. ARRAY, STRUCT-- 1. array_exercises 테이블에서 각 영화(title)별로 장르(genres)를 UNNEST해서 보여주세요. -- genres 꺼내기 SELECT title , genre FROM `advanced.array_exercises` CROSS JOIN UNNEST(genres) AS genre -- 2. array_exercises 테이블에서 각 영화(title)별로 배우(actor)와 배역(character)을 보여주세요. -- arrary 안의 struct 영화/배우 꺼내기 SELECT title , ac.actor , ac.character FROM `advanced.array_exercises` CROSS JOIN UNNEST(actors) AS ac -- actor.actor도 가능 -- 3. array_exercises 테이블에서 각 영화(title)별로 배우(actor)와 배역(character), 장르(genre) 출력 -- actors, genres 각각 꺼내기 (2번 조인) SELECT -- title, actor, character, genre title , ac.actor , ac.character , genre FROM `advanced.array_exercises` CROSS JOIN UNNEST(actors) AS ac CROSS JOIN UNNEST(genres) AS genre -- 4. 앱로그 데이터(app_logs)의 배열을 풀어주세요. -- event_params 꺼내기 SELECT user_id , event_date , event_name , user_pseudo_id , event_param.key , event_param.value.string_value , event_param.value.int_value FROM `advanced.app_logs` CROSS JOIN UNNEST(event_params) AS event_param -- WHERE event_date = '2022-08-01' -- test 2. PIVOT-- 1. orders 테이블에서 유저(user_id)별로 주문 금액(amount)의 합계를 PIOVT해주세요. -- 날짜(order_date)를 행, user_id를 열, sum(amount) SELECT order_date , SUM(IF(user_id = 1, amount, 0)) AS user_1 , SUM(IF(user_id = 2, amount, 0)) AS user_2 , SUM(IF(user_id = 3, amount, 0)) AS user_3 FROM `advanced.orders` GROUP BY 1 ORDER BY 1 -- 2. orders 테이블에서 날짜(order_date)별로 유저들의 주문 금액(amount) 합계를 PIVOT -- user_id 행, order_date 열, sum(주문 금액), '-' 포함 날짜 별칭은 backtick(``) 활용 SELECT user_id , SUM(IF(order_date = '2023-05-01', amount, 0)) AS `2023-05-01` , SUM(IF(order_date = '2023-05-02', amount, 0)) AS `2023-05-02` , SUM(IF(order_date = '2023-05-03', amount, 0)) AS `2023-05-03` , SUM(IF(order_date = '2023-05-04', amount, 0)) AS `2023-05-04` , SUM(IF(order_date = '2023-05-05', amount, 0)) AS `2023-05-05` FROM `advanced.orders` GROUP BY user_id ORDER BY user_id -- 3. orders 테이블에서 사용자별 날짜별로 주문이 있다면 1, 없으면 0으로 PIOVT -- user_id 행, order_date 열, if(날짜, 1, 0) SELECT user_id , MAX(IF(order_date = '2023-05-01', 1, 0)) AS `2023-05-01` , MAX(IF(order_date = '2023-05-02', 1, 0)) AS `2023-05-02` , MAX(IF(order_date = '2023-05-03', 1, 0)) AS `2023-05-03` , MAX(IF(order_date = '2023-05-04', 1, 0)) AS `2023-05-04` , MAX(IF(order_date = '2023-05-05', 1, 0)) AS `2023-05-05` FROM `advanced.orders` GROUP BY user_id ORDER BY user_id 3. 퍼널3-1. 퍼널별 유저 수-- 1. 퍼널별 유저 수 : 2022-08-01 ~ 2022-08-18, 오픈 퍼널, COUNT(DISTINCT user_pseudo_id) WITH funnels AS ( -- 조건/컬럼 필터링, event_params UNNEST, event name + screen 문자열 컬럼 병합 SELECT CONCAT(event_name, '-', event_param.value.string_value) AS event_name_with_screen , COUNT(DISTINCT user_pseudo_id) AS cnt FROM `advanced.app_logs` CROSS JOIN UNNEST(event_params) AS event_param WHERE event_date BETWEEN '2022-08-01' AND '2022-08-18' AND event_name IN ('screen_view', 'click_payment') AND event_param.key = 'firebase_screen' AND event_param.value.string_value NOT IN ('food_detail', 'search', 'search_result') GROUP BY ALL ) SELECT event_name_with_screen -- step_number 생성 , (CASE WHEN event_name_with_screen = 'screen_view-welcome' THEN 1 WHEN event_name_with_screen = 'screen_view-home' THEN 2 WHEN event_name_with_screen = 'screen_view-food_category' THEN 3 WHEN event_name_with_screen = 'screen_view-restaurant' THEN 4 WHEN event_name_with_screen = 'screen_view-cart' THEN 5 WHEN event_name_with_screen = 'click_payment-cart' THEN 6 END ) AS step_number , cnt FROM funnels ORDER BY step_number3-2. 퍼널별 유저 수(일자별)-- 2. 퍼널별 유저 수(일자별) : 2022-08-01 ~ 2022-08-18, 오픈 퍼널, COUNT(DISTINCT user_pseudo_id) WITH funnels AS ( -- 조건/컬럼 필터링, event_params UNNEST, event name + screen 문자열 컬럼 병합 SELECT -- 일자별 event_date , CONCAT(event_name, '-', event_param.value.string_value) AS event_name_with_screen , COUNT(DISTINCT user_pseudo_id) AS cnt FROM `advanced.app_logs` CROSS JOIN UNNEST(event_params) AS event_param WHERE event_date BETWEEN '2022-08-01' AND '2022-08-18' AND event_name IN ('screen_view', 'click_payment') AND event_param.key = 'firebase_screen' AND event_param.value.string_value NOT IN ('food_detail', 'search', 'search_result') GROUP BY ALL ) SELECT event_date , event_name_with_screen -- step_number 생성 , (CASE WHEN event_name_with_screen = 'screen_view-welcome' THEN 1 WHEN event_name_with_screen = 'screen_view-home' THEN 2 WHEN event_name_with_screen = 'screen_view-food_category' THEN 3 WHEN event_name_with_screen = 'screen_view-restaurant' THEN 4 WHEN event_name_with_screen = 'screen_view-cart' THEN 5 WHEN event_name_with_screen = 'click_payment-cart' THEN 6 END ) AS step_number , cnt FROM funnels ORDER BY event_date, step_number -- 정렬 변경 3-3. 퍼널별 유저 수(일자별 PIVOT)-- 3. 퍼널별 유저 수(일자별) 집계 PIVOT WITH funnels AS ( -- 조건/컬럼 필터링, event_params UNNEST, event name + screen 문자열 컬럼 병합 SELECT -- 일자별 event_date , CONCAT(event_name, '-', event_param.value.string_value) AS event_name_with_screen , COUNT(DISTINCT user_pseudo_id) AS cnt FROM `advanced.app_logs` CROSS JOIN UNNEST(event_params) AS event_param WHERE event_date BETWEEN '2022-08-01' AND '2022-08-18' AND event_name IN ('screen_view', 'click_payment') AND event_param.key = 'firebase_screen' AND event_param.value.string_value NOT IN ('food_detail', 'search', 'search_result') GROUP BY ALL ) SELECT event_date -- event PIVOT , MAX(IF(event_name_with_screen = 'screen_view-welcome', cnt, NULL)) AS `screen_view-welcome` , MAX(IF(event_name_with_screen = 'screen_view-home', cnt, NULL)) AS `screen_view-home` , MAX(IF(event_name_with_screen = 'screen_view-food_category', cnt, NULL)) AS `screen_view-food_category` , MAX(IF(event_name_with_screen = 'screen_view-restaurant', cnt, NULL)) AS `screen_view-restaurant` , MAX(IF(event_name_with_screen = 'screen_view-cart', cnt, NULL)) AS `screen_view-cart` , MAX(IF(event_name_with_screen = 'click_payment-cart', cnt, NULL)) AS `click_payment-cart` FROM funnels GROUP BY ALL ORDER BY event_date 

ARRAY, STRUCT 연습문제 1) SELECT title, genre FROM advanced.array_exercises CROSS JOIN UNNEST(genres) AS genre  2) SELECT title, actors, actors[SAFE_OFFSET(0)].actor AS frist_actor, actors[SAFE_OFFSET(0)].character AS first_character, actors[SAFE_OFFSET(1)].actor AS second_actor, actors[SAFE_OFFSET(1)].character AS second_character FROM advanced.array_exercises AS ae  3) SELECT title, actor.actor, actor.character FROM advanced.array_exercises AS ae CROSS JOIN UNNEST(actors) AS actor 4) SELECT event_Date, event_timestamp, event_name, event_params, user_id, event_param.key AS key, event_param.value AS value, event_param.value.string_value AS string_value, event_param.value.int_value AS int_value FROM advanced.app_logs_temp CROSS JOIN UNNEST(event_params) AS event_param WHERE event_date = '2022-08-01'PIVOT 연습문제1) SELECT order_date, SUM(IF(user_id = 1, sum_of_amount, 0)) AS user_1, SUM(IF(user_id = 2, sum_of_amount, 0)) AS user_2, SUM(IF(user_id = 3, sum_of_amount, 0)) AS user_3, FROM ( SELECT order_date, user_id, SUM(amount) AS sum_of_amount FROM advanced.orders GROUP BY order_date, user_id ORDER BY order_date) GROUP BY order_date2) SELECT user_id, SUM(IF(order_date = '2023-05-01', sum_of_amount, 0)) AS `2023-05-01`, SUM(IF(order_date = '2023-05-02', sum_of_amount, 0)) AS `2023-05-02`, SUM(IF(order_date = '2023-05-03', sum_of_amount, 0)) AS `2023-05-03`, SUM(IF(order_date = '2023-05-04', sum_of_amount, 0)) AS `2023-05-04`, SUM(IF(order_date = '2023-05-05', sum_of_amount, 0)) AS `2023-05-05` FROM ( SELECT user_id, order_date, SUM(amount) AS sum_of_amount FROM advanced.orders GROUP BY user_id,order_date) GROUP BY user_id 3) SELECT user_id, MAX(IF(order_date = '2023-05-01' AND user_id IS NOT NULL, 1, 0)) AS `2023-05-01`, MAX(IF(order_date = '2023-05-02' AND user_id IS NOT NULL, 1, 0)) AS `2023-05-02`, MAX(IF(order_date = '2023-05-03' AND user_id IS NOT NULL, 1, 0)) AS `2023-05-03`, MAX(IF(order_date = '2023-05-04' AND user_id IS NOT NULL, 1, 0)) AS `2023-05-04`, MAX(IF(order_date = '2023-05-05' AND user_id IS NOT NULL, 1, 0)) AS `2023-05-05` FROM advanced.orders GROUP BY user_id 4) SELECT event_date, event_timestamp, event_name, user_id, user_pseudo_id, MAX(IF(param.key = 'firebase_screen', param.value.string_value, NULL)) AS firebase_screen, MAX(IF(param.key = 'food_id', param.value.string_value, NULL)) AS food_id, MAX(IF(param.key = 'food_id', param.value.int_value, NULL)) AS food_id2, MAX(IF(param.key = 'session_id', param.value.string_value, NULL)) AS session_id FROM advanced.app_logs_temp CROSS JOIN UNNEST(event_params) AS param WHERE event_date = '2022-08-01' GROUP BY ALL  퍼널분석WITH Funnel AS (SELECT event_date, event_timestamp, event_name, user_id, user_pseudo_id, MAX(IF(param.key = 'firebase_screen', param.value.string_value, NULL)) AS firebase_screen, MAX(IF(param.key = 'food_id', param.value.string_value, NULL)) AS food_id, MAX(IF(param.key = 'food_id', param.value.int_value, NULL)) AS food_id2, MAX(IF(param.key = 'session_id', param.value.string_value, NULL)) AS session_id FROM advanced.app_logs_temp CROSS JOIN UNNEST(event_params) AS param WHERE event_date = '2022-08-01' GROUP BY ALL ) SELECT event_date, COUNT(user_id) AS user_cnt FROM Funnel WHERE event_name = 'click_cart' GROUP BY event_date; 

ARRAY, STRUCT, UNNEST 연습 문제array_exercises 테이블에서 각 영화(title)별로 장르(genres)를 UNNEST해서 보여주세요SELECT title, genre FROM `plucky-catfish-394207.advanced.array_exercises` , unnest(genres) as genre ORDER BY 1array_exercises 테이블에서 각 영화(title)별로 배우(actor)와 배역(character)을 보여주세요. 배우와 배역은 별도의 컬럼으로 나와야 합니다SELECT title, actor.actor, actor.character, FROM `plucky-catfish-394207.advanced.array_exercises` , unnest(genres) as genre ORDER BY 1array_exercises 테이블에서 각 영화(title)별로 배우(actor), 배역(character), 장르 (genre)를 출력하세요. 한 Row에 배우, 배역, 장르가 모두 표시되어야 합니다 SELECT title, actor.actor, genre, FROM `plucky-catfish-394207.advanced.array_exercises` , unnest(genres) as genre , unnest(actors) as actors ORDER BY 1앱 로그 데이터(app_logs)의 배열을 풀어주세요SELECT user_id, event_date, event_name, user_pseudo_id, ep.key, ep.value.string_value, ep.value.int_value FROM `plucky-catfish-394207.advanced.array_exercises` , unnest(event_params) as ep ORDER BY 2 PIVOTorders 테이블에서 유저(user_id)별로 주문 금액(amount)의 합계를 PIVOT해주세요. 날짜(order_date)를 행(Row)으로, user_id를 열(Column)으로 만들어야 합니다SELECT order_date, SUM(IF(user_id = 1, amount, 0) as user_1, SUM(IF(user_id = 2, amount, 0) as user_2, SUM(IF(user_id = 3, amount, 0) as user_3, FROM `plucky-catfish-394207.advanced.array_exercises` , unnest(event_params) as ep GROUP BY 1 ORDER BY 1orders 테이블에서 날짜(order_date)별로 유저들의 주문 금액(amount)의 합계를 PIVOT 해주세요. user_id를 행(Row)으로, order_date를 열(Column)으로 만들어야 합니다 SELECT user_id, SUM(IF(order_date = '2023-05-01', amount, 0) as `2023-05-01`, SUM(IF(order_date = '2023-05-02', amount, 0) as `2023-05-02`, SUM(IF(order_date = '2023-05-03', amount, 0) as `2023-05-03`, SUM(IF(order_date = '2023-05-04', amount, 0) as `2023-05-04`, SUM(IF(order_date = '2023-05-05', amount, 0) as `2023-05-05`, FROM `plucky-catfish-394207.advanced.array_exercises` , unnest(event_params) as ep GROUP BY 1 ORDER BY 1orders 테이블에서 사용자(user_id)별, 날짜(order_date)별로 주문이 있다면 1, 없다면 0으로 PIVOT 해주세요. user_id를 행(Row)으로, order_date를 열(Column)로 만들고 주문을 많이 해도 1로 처리합니다 SELECT user_id, SUM(IF(order_date = '2023-05-01', amount > 0, 1, 0) as `2023-05-01`, SUM(IF(order_date = '2023-05-02', amount > 0, 1, 0) as `2023-05-02`, SUM(IF(order_date = '2023-05-03', amount > 0, 1, 0) as `2023-05-03`, SUM(IF(order_date = '2023-05-04', amount > 0, 1, 0) as `2023-05-04`, SUM(IF(order_date = '2023-05-05', amount > 0, 1, 0) as `2023-05-05`, FROM `plucky-catfish-394207.advanced.array_exercises` , unnest(event_params) as ep GROUP BY 1 ORDER BY 1user_id = 32888이 카트 추가하기(click_cart)를 누를때 어떤 음식(food_id)을 담았나요? SELECT event_date, event_name, event_timestamp, user_id, user_pseudo_id, MAX(IF(ep.key = 'firebase_screen', ep.value.string_value, NULL)) as firebase_screen, MAX(IF(ep.key = 'food_id', ep.value.int_value, NULL)) as food_id, MAX(IF(ep.key = 'session_id', ep.value.int_value, NULL)) as session_id, FROM `plucky-catfish-394207.advanced.array_exercises` , unnest(event_params) as ep WHERE event_date = '2022-08-01' AND user_id = 32888 GROUP BY 1, 2, 3, 4, 5 퍼널 분석WITH base AS ( SELECT event_date event_timestamp, event_name, user_id, user_pseudo_id, platform, MAX(IF(event_param.key = "firebase_screen", event_param.value.string_value, NULL)) AS firebase_screen, MAX(IF(event_param.key = "session_id", event_param.value.string_value, NULL)) AS session_id FROM advanced.app_logs CROSS JOIN UNNEST(event_params) AS event_param WHERE event_date BETWEEN "2022-08-01" AND "2022-08-18" GROUP BY ALL ), filter_event_and_concat_event_and_screen AS ( SELECT * EXCEPT(event_name, firebase_screen, event_timestamp), CONCAT(event_name, "-", firebase_screen) AS event_name_with_screen, DATETIME(TIMESTAMP_MICROS(event_timestamp), 'Asia/Seoul') AS event_datetime FROM base WHERE event_name IN ("screen_view", "click_payment") ), add_step_number AS ( SELECT event_date, event_name_with_screen, CASE WHEN event_name_with_screen = "screen_view-welcome" THEN 1 WHEN event_name_with_screen = "screen_view-home" THEN 2 WHEN event_name_with_screen = "screen_view-food_category" THEN 3 WHEN event_name_with_screen = "screen_view-restaurant" THEN 4 WHEN event_name_with_screen = "screen_view-cart" THEN 5 WHEN event_name_with_screen = "click_payment-cart" THEN 6 ELSE NULL END AS step_number, COUNT(DISTINCT user_pseudo_id) AS cnt FROM filter_event_and_concat_event_and_screen GROUP BY ALL HAVING step_number IS NOT NULL

ARRAY, STRUCT-- array_exercises 테이블에서 각 영화(title)별로 장르(genres)를 UNNEST해서 보여주기. SELECT title, genre FROM advanced.array_exercises CROSS JOIN UNNEST(genres) as genre-- array_exercises 테이블에서 각 영화(title)별로 배우(actor)와 배역(character)을 보여주기. 단, 배우와 배역은 별도의 컬럼으로 나와야 함. SELECT title, actor.actor, actor.character FROM `advanced.array_exercises` CROSS JOIN UNNEST(actors) as actor-- array_exercises 테이블에서 각 영화(title)별로 배우(actor), 배역(character), 장르(genre) 출력하기 한 행에 배우, 배역, 장르가 모두 표시되어야 된다. SELECT title, actor.actor, actor.character, genre FROM `advanced.array_exercises` CROSS JOIN UNNEST(actors) as actor CROSS JOIN UNNEST(genres) as genre -- 앱 로그 데이터 (app_logs)의 배열 풀기 SELECT user_id, event_date, event_name, user_pseudo_id, event_param.key, event_param.value.string_value, event_param.value.int_value FROM advanced.app_logs CROSS JOIN UNNEST(event_params) as event_param limit 500 데이터 PIVOT-- orders 테이블에서 유저(user_id)별로 주문 금액(amount)의 합계를 PIVOT하기. 날짜(order_date)를 행(Row)으로, user_id를 열(Column)으로 만들어야됨. SELECT order_date, SUM(IF(user_id = 1,amount,0)) AS user_1, SUM(IF(user_id = 2,amount,0)) AS user_2, SUM(IF(user_id = 3,amount,0)) AS user_3 FROM advanced.orders GROUP BY order_date ORDER BY order_date asc;-- orders 테이블에서 날짜(order_date)별로 유저들의 주문 금액(amount)의 합계를 PIVOT하기. user_id를 행으로, order_date를 열로 만들어야 됨. SELECT user_id, sum(if(order_date = '2023-05-01',amount, 0)) AS `2023-05-01`, sum(if(order_date = '2023-05-02',amount, 0)) AS `2023-05-02`, sum(if(order_date = '2023-05-03',amount, 0)) AS `2023-05-03`, sum(if(order_date = '2023-05-04',amount, 0)) AS `2023-05-04`, sum(if(order_date = '2023-05-05',amount, 0)) AS `2023-05-05` FROM advanced.orders GROUP BY user_id ORDER BY user_id ASC-- orders 테이블에서 사용자(user_id)별, 날짜(order_date)별로 주문이 있다면 1, 없다면 0으로 피벗하기. user_id를 행으로, order_date를 열로 만들고 주문이 많아도 1로 처리. SELECT user_id, sum(if(order_date = '2023-05-01',1, 0)) AS `2023-05-01`, sum(if(order_date = '2023-05-02',1, 0)) AS `2023-05-02`, sum(if(order_date = '2023-05-03',1, 0)) AS `2023-05-03`, sum(if(order_date = '2023-05-04',1, 0)) AS `2023-05-04`, sum(if(order_date = '2023-05-05',1, 0)) AS `2023-05-05` FROM advanced.orders GROUP BY user_id ORDER BY user_id ASC-- 앱 로그 데이터 배열 PIVOT 하기 ( user_id = 32888이 카트 추가하기 (click_cart)를 누를때 어떤 음식(food_id)을 담았나?) WITH app_pivot AS ( SELECT user_id, event_date, event_name, user_pseudo_id, event_param.key AS key, event_param.value.string_value AS string_value, event_param.value.int_value AS int_value FROM advanced.app_logs CROSS JOIN UNNEST(event_params) as event_param ) SELECT user_id, event_date, event_name, user_pseudo_id, MAX(IF(key = 'firebase_screen', string_value,NULL)) AS `firebase_screen`, MAX(IF(key = 'food_id',int_value,NULL)) AS `food_id`, MAX(IF(key = 'session_id',string_value,NULL)) AS `session_id` FROM app_pivot WHERE user_id = 32888 AND event_name = 'click_cart' GROUP BY user_id,event_date, event_name, user_pseudo_id ORDER BY event_date ASC;퍼널 분석-- 일자별 이벤트 별 집계형태를 PIVOT 형태로 전환하기 WITH param_pivot AS ( SELECT event_date, event_timestamp, event_name, user_id, user_pseudo_id, MAX(IF(key = 'firebase_screen', event_param.value.string_value,NULL)) AS `firebase_screen`, MAX(IF(key = 'food_id',event_param.value.int_value,NULL)) AS `food_id`, MAX(IF(key = 'session_id',event_param.value.string_value,NULL)) AS `session_id` FROM advanced.app_logs CROSS JOIN UNNEST(event_params) AS event_param WHERE event_date BETWEEN '2022-08-01' AND '2022-08-18' GROUP BY ALL), event_table AS (SELECT * EXCEPT(event_name,firebase_screen), CONCAT(event_name,'_', firebase_screen) AS event_name_with_screen, FROM param_pivot WHERE event_name IN ('screen_view','click_payment') GROUP BY all ORDER BY event_date ASC ) , final AS (SELECT event_date, event_name_with_screen, (CASE WHEN event_name_with_screen = 'screen_view_welcome' THEN 1 WHEN event_name_with_screen = 'screen_view_home' THEN 2 WHEN event_name_with_screen = 'screen_view_food_category' THEN 3 WHEN event_name_with_screen = 'screen_view_restaurant' THEN 4 WHEN event_name_with_screen = 'screen_view_cart' THEN 5 WHEN event_name_with_screen = 'clik_payment_cart' THEN 6 ELSE NULL END ) AS step_number, COUNT( DISTINCT user_pseudo_id) AS cnt FROM event_table GROUP BY event_date, event_name_with_screen HAVING step_number IS NOT NULL ORDER BY event_date) SELECT event_date, SUM(IF(event_name_with_screen = 'screen_view_welcome', cnt, 0)) AS `screen_view_welcom`, SUM(IF(event_name_with_screen = 'screen_view_home', cnt, 0)) AS `screen_view_home`, SUM(IF(event_name_with_screen = 'screen_view_food_category', cnt, 0)) AS `screen_view_food_category`, SUM(IF(event_name_with_screen = 'screen_view_restaurant', cnt, 0)) AS `screen_view_restaurant`, SUM(IF(event_name_with_screen = 'screen_view_cart', cnt, 0)) AS `screen_view_cart`, SUM(IF(event_name_with_screen = 'click_payment_cart', cnt, 0)) AS `click_payment_cart` FROM final GROUP BY event_date ORDER BY event_date ASC;

1. ARRAY, STRUCT 연습문제(1) array_exercises 테이블에서 각 영화(title)별로 장르(genres)를 UNNEST해서 보여주세요.SELECT title, genre FROM advanced.array_exercises AS ae CROSS JOIN UNNEST(genres) AS genre*UNNEST(ARRAY_Column) = UNNEST(배열)(2) array_exercises 테이블에서 각 영화(title)별로 배우(actor)와 배역(character)을 보여주세요.배우와 배역은 별도의 컬럼으로 나와야 합니다.SELECT title, actor.actor, actor.character FROM advanced.array_exercises AS ae CROSS JOIN UNNEST(actors) AS actor(3) array_exercises 테이블에서 각 영화(title)별로 배우(actor)와 배역(character), 장르(genre)를 출력하세요. 한 Row에 배우, 배역, 장르가 모두 표시되어야 합니다.SELECT title, actor.actor, actor.character, genre FROM advanced.array_exercises AS ae , UNNEST(actors) AS actor , UNNEST(genres) AS genre*연속해서 CROSS JOIN UNNEST 사용 가능(4) 앱 로그 데이터(app_logs)의 배열을 풀어주세요.SELECT user_id, event_date, event_name, user_pseudo_id, event_param.key AS key, event_param.value.string_value AS string_value, event_param.value.int_value AS int_value FROM advanced.app_logs , UNNEST(event_params) AS event_param -- WHERE -- event_date = "2022-08-01"*실습 시, 파티션 사용 필요2. PIVOT 연습문제(1) orders 테이블에서 유저(user_id)별로 주문 금액(amount)의 합계를 PIVOT 해주세요.날짜(order_date)를 행(row)으로, user_id를 열(column)으로 만들어야 합니다.SELECT order_date, MAX(IF(user_id = 1, sum_of_amount, 0)) AS user_1, MAX(IF(user_id = 2, sum_of_amount, 0)) AS user_2, MAX(IF(user_id = 3, sum_of_amount, 0)) AS user_3 FROM ( SELECT order_date, user_id, SUM(amount) AS sum_of_amount FROM advanced.orders GROUP BY order_date, user_id ORDER BY order_date ) GROUP BY order_date ORDER BY order_date*첫번째 풀이 내 집계 함수 사용 시, GROUP BY 잊지않기*ctrl+d 사용(2) orders 테이블에서 날짜(order_date)별로 유저들의 주문 금액(amount)의 합계를 PIVOT 해주세요.user_id를 행(row)으로, order_date를 열(column)으로 만들어야 합니다.SELECT user_id, MAX(IF(order_date = '2023-05-01', amount, 0)) AS `2023-05-01`, MAX(IF(order_date = '2023-05-02', amount, 0)) AS `2023-05-02`, MAX(IF(order_date = '2023-05-03', amount, 0)) AS `2023-05-03`, MAX(IF(order_date = '2023-05-04', amount, 0)) AS `2023-05-04`, MAX(IF(order_date = '2023-05-05', amount, 0)) AS `2023-05-05`, FROM advanced.orders GROUP BY user_id ORDER BY user_id(3) orders 테이블에서 사용자(user_id)별, 날짜(order_date)별로 주문이 있다면 1, 없다면 0으로 해주세요. user_id를 행(row)으로, order_date를 열(column)로 만들고 주문을 많이 해도 1로 처리합니다.SELECT user_id, MAX(IF(order_date = '2023-05-01', 1, 0)) AS `2023-05-01`, MAX(IF(order_date = '2023-05-02', 1, 0)) AS `2023-05-02`, MAX(IF(order_date = '2023-05-03', 1, 0)) AS `2023-05-03`, MAX(IF(order_date = '2023-05-04', 1, 0)) AS `2023-05-04`, MAX(IF(order_date = '2023-05-05', 1, 0)) AS `2023-05-05`, FROM advanced.orders GROUP BY user_id ORDER BY user_id(4) user_id = 32888이 카트 추가하기(click_cart)를 누를 때 어떤 음식(food_id)을 담았나요?WITH base AS ( SELECT event_date, event_timestamp, event_name, user_id, user_pseudo_id, MAX(IF(event_param.key = 'firebase screen', event_param.value.string_value, NULL)) AS firebase_screen, MAX(IF(event_param.key = 'food_id', event_param.value.int_value, null)) AS food_id, MAX(IF(event_param.key = 'session_id', event_param.value.string_value, null)) AS session_id FROM advanced.app_logs , UNNEST(event_params) AS event_param GROUP BY ALL ) SELECT food_id FROM base WHERE user_id = 32888 AND event_name = 'click_cart' GROUP BY food_id3. 퍼널 분석 연습문제(1) 각 퍼널의 유저 수를 집계 데이터 : 2022-08-01 ~ 2022-08-18WITH base AS( SELECT event_date, event_timestamp, event_name, user_id, user_pseudo_id, platform, MAX(IF(event_param.key = "firebase_screen", event_param.value.string_value, NULL)) AS firebase_screen, MAX(IF(event_param.key = "food_id", event_param.value.int_value, NULL)) AS food_id, MAX(IF(event_param.key = "session_id", event_param.value.int_value, NULL)) AS session_id FROM `advanced.app_logs` CROSS JOIN UNNEST(event_params) AS event_param GROUP BY ALL ), filter_event_and_concat_event_and_screen AS( SELECT * EXCEPT(event_name, firebase_screen), CONCAT(event_name, "-", firebase_screen) AS event_name_with_screen, DATETIME(TIMESTAMP_MICROS(event_timestamp), "Asia/Seoul") AS event_datetime FROM base WHERE event_date BETWEEN "2022-08-01" AND "2022-08-18" AND event_name IN ("screen_view", "click_payment") AND firebase_screen IN ("welcome", "home", "food_category", "restaurant", "cart") ) SELECT event_date, event_name_with_screen, CASE WHEN event_name_with_screen = 'screen_view-welcome' THEN 1 WHEN event_name_with_screen = 'screen_view-home' THEN 2 WHEN event_name_with_screen = 'screen_view-food_category' THEN 3 WHEN event_name_with_screen = 'screen_view-restaurant' THEN 4 WHEN event_name_with_screen = 'screen_view-cart' THEN 5 WHEN event_name_with_screen = 'click_payment-cart' THEN 6 ELSE NULL END AS step_number, COUNT(DISTINCT user_pseudo_id) AS cnt FROM filter_event_and_concat_event_and_screen GROUP BY ALL HAVING step_number IS NOT NULL ORDER BY event_date, step_number 

ARRAY, STRUCT1) array_exercises 테이블에서 각 영화(title)별로 장르(genres)를 UNNEST해서 보여주세요.SELECT title, genre FROM advanced.array_exercises CROSS JOIN UNNEST(genres) as genre2) array_exercises 테이블에서 각 영화(title)별로 배우(actor)와 배역(character)을 보여주세요. 배우와 배역은 별도의 컬럼으로 나와야 합니다.SELECT title, actor.actor, actor.character FROM advanced.array_exercises CROSS JOIN UNNEST(actors) as actor3) array_exercises 테이블에서 각 영화(title)별로 배우(actor), 배역(character), 장르 (genre)를 출력하세요. 한 Row에 배우, 배역, 장르가 모두 표시되어야 합니다.SELECT title, actor.actor as actor, actor.character as character, genre FROM advanced.array_exercises CROSS JOIN UNNEST(genres) as genre CROSS JOIN UNNEST(actors) as actor ORDER BY 1, 2 desc4) 앱 로그 데이터(app_logs)의 배열을 풀어주세요.SELECT user_id, event_date, event_name, user_pseudo_id, evnent_parm.key AS key, evnent_parm.value.string_value AS string_value, evnent_parm.value.int_value AS int_value, FROM advanced.app_logs, UNNEST(event_params) AS evnent_parm PIVOT1) orders 테이블에서 유저(user_id)별로 주문 금액(amount)의 합계를 PIVOT해주세요. 날짜(order_date)를 행(Row)으로, user_id를 열(Column)으로 만들어야 합니다.SELECT order_date, SUM(IF(user_id=1,amount,0)) AS user_1, SUM(IF(user_id=2,amount,0)) AS user_2, SUM(IF(user_id=3,amount,0)) AS user_3 FROM advanced.orders GROUP BY order_date ORDER BY order_date;2) orders 테이블에서 날짜(order_date)별로 유저들의 주문 금액(amount)의 합계를 PIVOT 해주세요. user_id를 행(Row)으로, order_date를 열(Column)으로 만들어야 합니다.SELECT user_id, COALESCE(SUM(IF(order_date = '2023-05-01', amount, null)),0) AS `2023-05-01`, COALESCE(SUM(IF(order_date = '2023-05-02', amount, null)),0) AS `2023-05-02`, COALESCE(SUM(IF(order_date = '2023-05-03', amount, null)),0) AS `2023-05-03`, COALESCE(SUM(IF(order_date = '2023-05-04', amount, null)),0) AS `2023-05-04`, COALESCE(SUM(IF(order_date = '2023-05-05', amount, null)),0) AS `2023-05-05`, FROM advanced.orders GROUP BY user_id ORDER BY user_id;3) orders 테이블에서 사용자(user_id)별, 날짜(order_date)별로 주문이 있다면 1, 없다면 0으로 PIVOT 해주세요. user_id를 행(Row)으로, order_date를 열(Column)로 만들고 주문을 많이 해도 1로 처리합니다.SELECT user_id, MAX(IF(order_date = '2023-05-01' AND order_id is not null, 1, 0)) AS `2023-05-01`, MAX(IF(order_date = '2023-05-02' AND order_id is not null, 1, 0)) AS `2023-05-02`, MAX(IF(order_date = '2023-05-03' AND order_id is not null, 1, 0)) AS `2023-05-03`, MAX(IF(order_date = '2023-05-04' AND order_id is not null, 1, 0)) AS `2023-05-04`, MAX(IF(order_date = '2023-05-05' AND order_id is not null, 1, 0)) AS `2023-05-05`, FROM advanced.orders GROUP BY user_id ORDER BY user_id; 퍼널 분석1) 퍼널 별 유저 수 집계데이터 : 2022-08-01 ~ 2022-08-18WITH funnel_data_raw AS ( SELECT event_date, event_timestamp, event_name, user_id, user_pseudo_id, MAX(IF(pr.key = 'firebase_screen', pr.value.string_value, null)) AS screen_name, CONCAT(event_name, '-', MAX(IF(pr.key = 'firebase_screen', pr.value.string_value, null))) AS event_name_with_screen FROM advanced.app_logs, UNNEST(event_params) AS pr WHERE event_date BETWEEN '2022-08-01' AND '2022-08-18' GROUP BY 1,2,3,4,5 ) SELECT event_name_with_screen, CASE WHEN event_name_with_screen = 'screen_view-welcome' THEN 1 WHEN event_name_with_screen = 'screen_view-home' THEN 2 WHEN event_name_with_screen = 'screen_view-food_category' THEN 3 WHEN event_name_with_screen = 'screen_view-restaurant' THEN 4 WHEN event_name_with_screen = 'screen_view-cart' THEN 5 WHEN event_name_with_screen = 'click_payment-cart' THEN 6 END AS step_number, COUNT(DISTINCT user_pseudo_id) AS cnt FROM funnel_data_raw WHERE event_name IN ('screen_view', 'click_payment') AND screen_name IN ('welcome', 'home', 'food_category', 'restaurant', 'cart') GROUP BY 1,2 ORDER BY 2 ;2) 퍼널 별 유저 수 집계 (일자별)WITH funnel_data_raw AS ( SELECT event_date, event_timestamp, event_name, user_id, user_pseudo_id, MAX(IF(pr.key = 'firebase_screen', pr.value.string_value, null)) AS screen_name, CONCAT(event_name, '-', MAX(IF(pr.key = 'firebase_screen', pr.value.string_value, null))) AS event_name_with_screen FROM advanced.app_logs, UNNEST(event_params) AS pr WHERE event_date BETWEEN '2022-08-01' AND '2022-08-18' GROUP BY 1,2,3,4,5 ) SELECT event_date, event_name_with_screen, CASE WHEN event_name_with_screen = 'screen_view-welcome' THEN 1 WHEN event_name_with_screen = 'screen_view-home' THEN 2 WHEN event_name_with_screen = 'screen_view-food_category' THEN 3 WHEN event_name_with_screen = 'screen_view-restaurant' THEN 4 WHEN event_name_with_screen = 'screen_view-cart' THEN 5 WHEN event_name_with_screen = 'click_payment-cart' THEN 6 END AS step_number, COUNT(DISTINCT user_pseudo_id) AS cnt FROM funnel_data_raw WHERE event_name IN ('screen_view', 'click_payment') AND screen_name IN ('welcome', 'home', 'food_category', 'restaurant', 'cart') GROUP BY 1,2,3 ORDER BY 1,3 ;3) 집계한 데이터를 PIVOT-- 연구 및 추가적 작업 필요 배운점대용량의 복잡한 데이터를 의도에 따라 구조화 및 시각화하는 기초 지식을 습득함. 과업이 복잡해지면 쿼리가 깔끔하게 정리가 되지 않거나 스텝이 꼬이는 등의 어려움을 겪기도 함.각 연습문제에 대해 '왜이 쿼리를 실행하는 것이며, 그 결과값을 통해 어떤 추가적인 Action을 취할 수 있는가' 실무 관점으로 고민해보는 계기가 되었음.

연습문제CREATE OR REPLACE TABLE advanced.array_excercised AS #DDL SELECT movie_id, title, actors, genres FROM ( SELECT 1 AS movie_id, 'Avengers: Endgame' AS title, ARRAY<STRUCT<actor STRING, character STRING>>[ STRUCT('Robert Downey Jr.', 'Tony Stark'), STRUCT('Chris Evans', 'Steve Rogers') ] AS actors, ARRAY<STRING>['Action', 'Adventure', 'Drama'] AS genres UNION ALL SELECT 2, 'Inception', ARRAY<STRUCT<actor STRING,character STRING>>[ STRUCT('leonardo DiCaprio', 'Cobb'), STRUCT('Joseph Gordon-Levitt', 'Arthur') ], ARRAY<STRING>['Action', 'Adventure', 'Sci-Fi'] UNION ALL SELECT 3, 'The Dark Knight', ARRAY<STRUCT<actor STRING, character STRING>>[ STRUCT('Christian Bale', 'Bruce Wayne'), STRUCT('Heath Ledger', 'Joker') ], ARRAY<STRING>['Action', 'Crime', 'Drama'] ) → actors라는 STRUCT 구조체를 만들고 그 안에 2개의 필드 actor와 character를 지정하고, STRUCT 구조체 2개를 list처럼 ARRAY에 넣은 것.위의 테이블을 가지고 연습문제 1~4번 진행array_excercises 테이블에서 각 영화(title)별로 장르(genres)를 UNNEST해서 보여주세요.SELECT title, genre FROM advanced.array_excercised CROSS JOIN UNNEST(genres) AS genre  array_excercised 테이블에서 각 영화(title)별로 배우(actor)와 배역(character)을 보여주세요. 배우와 배역은 별도의 컬럼으로 나와야 합니다.SELECT title, actor.actor, actor.character FROM advanced.array_excercised CROSS JOIN UNNEST(actors) AS actor actors ARRAY안에 2개의 STRUCT 구조체가 있는 구조이므로 ARRAY 데이터에 접근하는 방법으로 데이터에는 접근 가능actors[SAFE_OFFSET(0)].actor AS first_actorarray_excercises 테이블에서 각 영화(title)별로 배우(actor), 배역(character), 장르(genre)를 출력하세요. 한 Row에 배우, 배역, 장르가 모두 표시되어야 합니다.SELECT title, actor.actor, actor.character, genre FROM advanced.array_excercised CROSS JOIN UNNEST(actors) AS actor CROSS JOIN UNNEST(genres) AS genre *UNNEST를 2번 연속 사용할 수 있다.*쿼리문의 실행순서는 FROM → JOIN → SELECT 이다. UNNEST를 통해 만들어진 actor는 현재 actor.actor가 아니라 actor라는 STRUCT 구조체이므로 구조체에 바로 접근할 수 없다는 에러가 뜰 수 있다.앱 로그 데이터(app_logs)의 배열을 풀어주세요.  SELECT event_date, event_timestamp, event_name, event_param.key AS key, event_param.value AS value, user_id, user_pseudo_id, platform FROM advanced.app_logs CROSS JOIN UNNEST(event_params) AS event_paramevent_params는 RECORD라고 되어있는데 STRUCT이다. 중첩된 구조라는 의미.PIVOT 연습문제orders 테이블에서 유저(user_id)별로 주문 금액(amount)의 합계를 PIVOT해주세요. 날짜(order_date)를 행(Row)으로, user_id를 열(column)으로 만들어야 합니다.SELECT order_date, SUM(IF(user_id = 1, amount, 0)) AS user_1, SUM(IF(user_id = 2, amount, 0)) AS user_2, SUM(IF(user_id = 3, amount, 0)) AS user_3 FROM advanced.orders GROUP BY order_date ORDER BY order_date 2. orders 테이블에서 날짜(order_date)별로 유저들의 주문 금액(amount)의 합계를 PIVOT해주세요. user_id를 행(Row)으로, order_date를 열(Column)으로 만들어야 합니다.SELECT user_id, SUM(IF(order_date = "2023-05-01", amount, 0)) AS `2023-05-01`, SUM(IF(order_date = "2023-05-02", amount, 0)) AS `2023-05-02`, SUM(IF(order_date = "2023-05-03", amount, 0)) AS `2023-05-03`, SUM(IF(order_date = "2023-05-04", amount, 0)) AS `2023-05-04`, SUM(IF(order_date = "2023-05-05", amount, 0)) AS `2023-05-05` FROM advanced.orders GROUP BY user_id orders 테이블에서 사용자(user_id)별, 날짜(order_date)별로 주문이 있다면 1, 없다면 0으로 PIVOT해주세요. user_id를 행(Row)으로, order_date를 열(Column)로 만들고 주문을 많이 해도 1로 처리합니다.SELECT user_id, MAX(IF(order_date = "2023-05-01", 1, 0)) AS `2023-05-01`, MAX(IF(order_date = "2023-05-02", 1, 0)) AS `2023-05-02`, MAX(IF(order_date = "2023-05-03", 1, 0)) AS `2023-05-03`, MAX(IF(order_date = "2023-05-04", 1, 0)) AS `2023-05-04`, MAX(IF(order_date = "2023-05-05", 1, 0)) AS `2023-05-05` FROM advanced.orders GROUP BY user_id 4. user_id = 32888이 카트 추가하기(click_cart)를 누를 때 어떤 음식(food_id)을 담았나요?WITH base AS( SELECT #* EXCEPT(event_params), event_date, event_timestamp, event_name, event_param.key AS key, event_param.value.string_value AS string_value, event_param.value.int_value AS int_value, user_id, user_pseudo_id, platform FROM advanced.app_logs CROSS JOIN UNNEST(event_params) AS event_param ) SELECT user_id, event_date, event_name, MAX(IF(key = 'firebase_screen', string_value, NULL)) AS firebase_screen, MAX(IF(key = 'food_id', int_value, NULL)) AS food_id, MAX(IF(key = 'session_id', string_value, NULL)) AS session_id FROM base WHERE user_id = 32888 AND event_name = 'click_cart' GROUP BY user_id, event_date, event_name퍼널별 전환율을 쉽게 구할 수 있도록 PIVOT 해보기 WITH base AS ( SELECT event_date, event_timestamp, event_name, user_id, user_pseudo_id, platform, #event_param, MAX(IF(event_param.key = 'firebase_screen', event_param.value.string_value, NULL)) AS firebase_screen, #MAX(IF(event_param.key = 'food_id', event_param.value.int_value, NULL)) AS food_id, MAX(IF(event_param.key = 'session_id', event_param.value.string_value, NULL)) AS session_id FROM advanced.app_logs CROSS JOIN UNNEST(event_params) AS event_param WHERE #event_date = "2022-08-01" #적은 데이터로 쿼리를 작성하기 위해 만들어둔 조건 event_date BETWEEN "2022-08-01" AND "2022-08-18" GROUP BY ALL ), filter_event_and_concat_event_and_screen AS ( SELECT * EXCEPT(event_name, firebase_screen, event_timestamp), CONCAT(event_name, "-", firebase_screen) AS event_name_with_screen, DATETIME(TIMESTAMP_MICROS(event_timestamp), 'Asia/Seoul') AS event_datetime FROM base WHERE event_name IN ("screen_view", "click_payment") ), funnel_analysis AS ( SELECT event_date, #일자별로 퍼널별 유저수 쿼리 event_name_with_screen, CASE WHEN event_name_with_screen = "screen_view-welcome" THEN 1 WHEN event_name_with_screen = "screen_view-home" THEN 2 WHEN event_name_with_screen = "screen_view-food_category" THEN 3 WHEN event_name_with_screen = "screen_view-restaurant" THEN 4 WHEN event_name_with_screen = "screen_view-cart" THEN 5 WHEN event_name_with_screen = "click_payment-cart" THEN 6 ELSE NULL END AS step_number, COUNT(DISTINCT user_pseudo_id) AS cnt FROM filter_event_and_concat_event_and_screen GROUP BY ALL HAVING step_number IS NOT NULL ORDER BY event_date ) SELECT event_date, MAX(IF (event_name_with_screen = "screen_view-welcome", cnt, NULL)) AS `screen_view-welcome`, MAX(IF (event_name_with_screen = "screen_view-home", cnt, NULL)) AS `screen_view-home`, MAX(IF (event_name_with_screen = "screen_view-food_category", cnt, NULL)) AS `screen_view-food_category`, MAX(IF (event_name_with_screen = "screen_view-restaurant", cnt, NULL)) AS `screen_view-restaurant`, MAX(IF (event_name_with_screen = "screen_view-cart", cnt, NULL)) AS `screen_view-cart`, MAX(IF (event_name_with_screen = "click_payment-cart", cnt, NULL)) AS `click_payment-cart` FROM funnel_analysis GROUP BY ALL ORDER BY event_date  

1. ARRAY, STRUCT1) array_exercises 테이블에서 각 영화(title)별로 장르(genres)를 UNNEST해서 보여주세요.SELECT title , genre FROM advanced.array_exercises CROSS JOIN UNNEST(genres) AS genre ;2) array_exercises 테이블에서 각 영화(title)별로 배우(actor)와 배역(character)을 보여주세요. (배우와 배역은 별도의 컬럼으로 나와야 합니다)-- 동일한 단어에 대해 선택할 수 있는 함수 : cmd+d SELECT title , actor.actor , actor.character FROM advanced.array_exercises CROSS JOIN UNNEST(actors) AS actor ;3) array_exercises 테이블에서 각 영화(title)별로 배우(actor), 배역(character), 장르(genre)를 출력하세요. 한 Row에 배우, 배역, 장르가 모두 표시되어야 합니다.SELECT title , actor.actor , actor.character , genre FROM advanced.array_exercises CROSS JOIN UNNEST(actors) AS actor CROSS JOIN UNNEST(genres) AS genre ;4) 앱 로그 데이터(app_logs)의 배열을 풀어주세요.SELECT user_id , event_date , event_name , user_pseudo_id , event_param.key , event_param.value.string_value , event_param.value.int_value , platform FROM advanced.app_logs CROSS JOIN UNNEST(event_params) AS event_param ;2. PIVOT1) orders 테이블에서 유저(user_id)별로 주문 금액(amount)의 합계를 PIVOT해주세요. 날짜(order_date)를 행(Row)으로, user_id를 열(Column)으로 만들어야 합니다.SELECT order_date , SUM(IF(user_id = 1, amount, NULL)) AS `user_id_1` , SUM(IF(user_id = 2, amount, NULL)) AS `user_id_2` , SUM(IF(user_id = 3, amount, NULL)) AS `user_id_3` FROM advanced.orders GROUP BY 1 ORDER BY 1 ;2) orders 테이블에서 날짜(order_date)별로 유저들의 주문 금액(amount)의 합계를 PIVOT 해주세요. user_id를 행(Row)으로, order_date를 열(Column)으로 만들어야 합니다.SELECT user_id , SUM(IF(order_date = '2023-05-01', amount, 0)) AS `2023-05-01` , SUM(IF(order_date = '2023-05-02', amount, 0)) AS `2023-05-02` , SUM(IF(order_date = '2023-05-03', amount, 0)) AS `2023-05-03` , SUM(IF(order_date = '2023-05-04', amount, 0)) AS `2023-05-04` , SUM(IF(order_date = '2023-05-05', amount, 0)) AS `2023-05-05` FROM advanced.orders GROUP BY 1 ;3) orders 테이블에서 사용자(user_id)별, 날짜(order_date)별로 주문이 있다면 1, 없다면 0으로 PIVOT 해주세요. user_id를 행(Row)으로, order_date를 열(Column)로 만들고 주문을 많이 해도 1로 처리합니다SELECT user_id , MAX(IF(order_date = '2023-05-01', 1, 0)) AS `2023-05-01` , MAX(IF(order_date = '2023-05-02', 1, 0)) AS `2023-05-02` , MAX(IF(order_date = '2023-05-03', 1, 0)) AS `2023-05-03` , MAX(IF(order_date = '2023-05-04', 1, 0)) AS `2023-05-04` , MAX(IF(order_date = '2023-05-05', 1, 0)) AS `2023-05-05` FROM advanced.orders GROUP BY 1 ;4) user_id = 32888이 카트 추가하기(click_cart)를 누를 때 어떤 음식(food_id)을 담았나요?WITH app_logs_info AS ( SELECT user_id , event_name , MAX(IF(event_param.key = 'firebase_screen', event_param.value.string_value, NULL)) AS firebase_screen , MAX(IF(event_param.key = 'food_id', event_param.value.int_value, NULL)) AS food_id FROM advanced.app_logs CROSS JOIN UNNEST(event_params) AS event_param GROUP BY 1, 2 ) SELECT food_id FROM app_logs_info WHERE user_id = 32888 AND event_name = 'click_cart' ; 3. Funnel1) 일자별, 이벤트별 집계WITH app_logs_info AS ( SELECT user_id , event_date , event_timestamp , event_name , user_pseudo_id , event_param.key , MAX(IF(event_param.key = 'firebase_screen', event_param.value.string_value, NULL)) AS firebase_screen , MAX(IF(event_param.key = 'food_id', event_param.value.int_value, NULL)) AS food_id FROM advanced.app_logs CROSS JOIN UNNEST(event_params) AS event_param WHERE event_date BETWEEN '2022-08-01' AND '2022-08-18' AND event_name IN ('screen_view', 'click_payment') GROUP BY ALL ) , add_step_number AS ( SELECT event_date , DATETIME(TIMESTAMP_MICROS(event_timestamp), 'Asia/Seoul') AS event_date_time , user_id , user_pseudo_id , CONCAT(event_name, '-', firebase_screen) AS event_name_with_screen , CASE CONCAT(event_name, '-', firebase_screen) WHEN 'screen_view-welcome' THEN 1 WHEN 'screen_view-home' THEN 2 WHEN 'screen_view-food_category' THEN 3 WHEN 'screen_view-restaurant' THEN 4 WHEN 'screen_view-cart' THEN 5 WHEN 'click_payment-cart' THEN 6 ELSE NULL END AS step_number FROM app_logs_info ) SELECT event_date , step_number , event_name_with_screen , COUNT(DISTINCT user_pseudo_id) AS user_cnt FROM add_step_number WHERE step_number IS NOT NULL GROUP BY 1, 2, 3 ORDER BY 1, 2 ; 2) 집계 데이터 PIVOTWITH app_logs_info AS ( SELECT user_id , event_date , event_timestamp , event_name , user_pseudo_id , event_param.key , MAX(IF(event_param.key = 'firebase_screen', event_param.value.string_value, NULL)) AS firebase_screen , MAX(IF(event_param.key = 'food_id', event_param.value.int_value, NULL)) AS food_id FROM advanced.app_logs CROSS JOIN UNNEST(event_params) AS event_param WHERE event_date BETWEEN '2022-08-01' AND '2022-08-18' GROUP BY ALL ) , add_step_number AS ( SELECT event_date , DATETIME(TIMESTAMP_MICROS(event_timestamp), 'Asia/Seoul') AS event_date_time , user_id , user_pseudo_id , CONCAT(event_name, '-', firebase_screen) AS event_name_with_screen , CASE CONCAT(event_name, '-', firebase_screen) WHEN 'screen_view-welcome' THEN 1 WHEN 'screen_view-home' THEN 2 WHEN 'screen_view-food_category' THEN 3 WHEN 'screen_view-restaurant' THEN 4 WHEN 'screen_view-cart' THEN 5 WHEN 'click_payment-cart' THEN 6 ELSE NULL END AS step_number FROM app_logs_info WHERE event_name IN ('screen_view', 'click_payment') ) , agg_user_cnt AS ( SELECT event_date , step_number , event_name_with_screen , COUNT(DISTINCT user_pseudo_id) AS user_cnt FROM add_step_number WHERE step_number IS NOT NULL GROUP BY 1, 2, 3 ORDER BY 1, 2 ) SELECT event_date , MAX(IF(step_number = 1, user_cnt, NULL)) AS `screen_view-welcome` , MAX(IF(step_number = 2, user_cnt, NULL)) AS `screen_view-home` , MAX(IF(step_number = 3, user_cnt, NULL)) AS `screen_view-food_category` , MAX(IF(step_number = 4, user_cnt, NULL)) AS `screen_view-restaurant` , MAX(IF(step_number = 5, user_cnt, NULL)) AS `screen_view-cart` , MAX(IF(step_number = 6, user_cnt, NULL)) AS `click_payment-cart` FROM agg_user_cnt GROUP BY 1 ORDER BY 1 ;

안녕하세요 루키스님 강의에 질문이 있어서 글 작성합니다. rsp에 16을 더해주는 이유에 대해서 정확히 이해를 하지 못했습니다. push를 2회 하면서 이미 rsp가 16이 더해진 상태로 있다고 생각을 하고 있는데왜 또다시 16을 더해준것인지 잘 이해가 안갑니다.

예제 데이터 프레임에서 결측치를 np.nan으로 적어주셨는데, 결측치를 무조건 이렇게 사용해야 하는건가요?

1. ARRAY, STRUCT 연습문제연습문제 1SELECT title , genre FROM `advanced.array_exercises` CROSS JOIN UNNEST(genres) AS genre 연습문제 2SELECT title , actor.actor , actor.character FROM `advanced.array_exercises` CROSS JOIN UNNEST(actors) AS actor 연습문제 3SELECT title , actor.actor AS actor , actor.character AS character , genre FROM `advanced.array_exercises` CROSS JOIN UNNEST(actors) AS actor CROSS JOIN UNNEST(genres) AS genre[메모]여기서 CROSS JOIN 다음 라인에 WHERE actor = 'Chris Evans' 이렇게 조건을 걸어줄 경우 오류가 발생한다. 오류는 실행 순서와 관련이 있다. 실행 순서: FROM -> JOIN -> SELECT따라서 SELECT 에서 알리아스로 이름 붙인 actor 가 아닌, CROSS JOIN 결과를 사용하여 조건을 만들어야 한다. => WHERE actor.actor = 'Chris Evans'  연습문제 4SELECT user_id , event_date , event_name , user_pseudo_id , parameter.key AS key , parameter.value.string_value AS string_value , parameter.value.int_value AS int_value FROM `inflearn-bigquery-437203.advanced.app_logs` CROSS JOIN UNNEST (event_params) AS parameter WHERE event_date = "2022-08-01"  2. PIVOT 연습문제연습문제 1SELECT order_date , SUM(IF(user_id = 1, amount, 0)) AS user_1 , SUM(IF(user_id = 2, amount, 0)) AS user_2 , SUM(IF(user_id = 3, amount, 0)) AS user_3 FROM `inflearn-bigquery-437203.advanced.orders` GROUP BY order_date ORDER BY order_date 연습문제 2SELECT user_id , SUM(IF(order_date= '2023-05-01', amount, 0)) AS `2023-05-01` , SUM(IF(order_date= '2023-05-02', amount, 0)) AS `2023-05-02` , SUM(IF(order_date= '2023-05-03', amount, 0)) AS `2023-05-03` , SUM(IF(order_date= '2023-05-04', amount, 0)) AS `2023-05-04` , SUM(IF(order_date= '2023-05-05', amount, 0)) AS `2023-05-05` FROM `inflearn-bigquery-437203.advanced.orders` GROUP BY user_id ORDER BY user_id[메모]알리아스로 컬럼명 지정할 때, 영어 제외하고 다른 문자열가 포함될 경우 → backtick (`) 으로 감싸준다. 연습문제 3SELECT user_id , MAX(IF(order_date= '2023-05-01', 1, 0)) AS `2023-05-01` , MAX(IF(order_date= '2023-05-02', 1, 0)) AS `2023-05-02` , MAX(IF(order_date= '2023-05-03', 1, 0)) AS `2023-05-03` , MAX(IF(order_date= '2023-05-04', 1, 0)) AS `2023-05-04` , MAX(IF(order_date= '2023-05-05', 1, 0)) AS `2023-05-05` FROM `inflearn-bigquery-437203.advanced.orders` GROUP BY user_id ORDER BY user_id 연습문제 4SELECT event_date , event_timestamp , event_name , user_id , user_pseudo_id , MAX(IF(params.key = 'firebase_screen', params.value.string_value, NULL)) AS firebase_screen , MAX(IF(params.key = 'food_id', params.value.int_value, NULL)) AS food_id , MAX(IF(params.key = 'session_id', params.value.string_value, NULL)) AS session_id FROM `inflearn-bigquery-437203.advanced.app_logs` CROSS JOIN UNNEST(event_params) AS params WHERE event_date = '2022-08-01' GROUP BY ALL  3. 퍼널 쿼리 연습문제연습문제 1: 각 퍼널별 유저 수 집계-- 퍼널 단계: 6 -- screen_view(welcome) -- screen_view(home) -- screen_view(food_category) -- screen_view(restaurant) -- screen_view(cart) -- click_payment(cart) WITH funnel AS ( SELECT CONCAT(event_name, '-', param.value.string_value) AS event_name_with_screen , CASE WHEN event_name = 'screen_view' AND param.value.string_value = 'welcome' THEN 1 WHEN event_name = 'screen_view' AND param.value.string_value = 'home' THEN 2 WHEN event_name = 'screen_view' AND param.value.string_value = 'food_category' THEN 3 WHEN event_name = 'screen_view' AND param.value.string_value = 'restaurant' THEN 4 WHEN event_name = 'screen_view' AND param.value.string_value = 'cart' THEN 5 WHEN event_name = 'click_payment' AND param.value.string_value = 'cart' THEN 6 END AS step_number , user_pseudo_id FROM `inflearn-bigquery-437203.advanced.app_logs` CROSS JOIN UNNEST(event_params) AS param WHERE event_date BETWEEN '2022-08-01' AND '2022-08-18' AND event_name IN ('screen_view', 'click_payment') AND param.key = 'firebase_screen' AND param.value.string_value IN ('welcome', 'home', 'food_category', 'restaurant', 'cart') ) SELECT event_name_with_screen , MAX(step_number) AS step_number , COUNT(DISTINCT user_pseudo_id) AS cnt FROM funnel GROUP BY event_name_with_screen 연습문제 2: 일자별 각 퍼널의 유저 수 집계-- 퍼널 단계: 6 -- screen_view(welcome) -- screen_view(home) -- screen_view(food_category) -- screen_view(restaurant) -- screen_view(cart) -- click_payment(cart) WITH funnel AS ( SELECT event_date -- 날짜 컬럼 추가 , CONCAT(event_name, '-', param.value.string_value) AS event_name_with_screen , CASE WHEN event_name = 'screen_view' AND param.value.string_value = 'welcome' THEN 1 WHEN event_name = 'screen_view' AND param.value.string_value = 'home' THEN 2 WHEN event_name = 'screen_view' AND param.value.string_value = 'food_category' THEN 3 WHEN event_name = 'screen_view' AND param.value.string_value = 'restaurant' THEN 4 WHEN event_name = 'screen_view' AND param.value.string_value = 'cart' THEN 5 WHEN event_name = 'click_payment' AND param.value.string_value = 'cart' THEN 6 END AS step_number , user_pseudo_id FROM `inflearn-bigquery-437203.advanced.app_logs` CROSS JOIN UNNEST(event_params) AS param WHERE event_date BETWEEN '2022-08-01' AND '2022-08-18' AND event_name IN ('screen_view', 'click_payment') AND param.key = 'firebase_screen' AND param.value.string_value IN ('welcome', 'home', 'food_category', 'restaurant', 'cart') ) SELECT event_date -- 날짜 컬럼 추가 , event_name_with_screen , MAX(step_number) AS step_number , COUNT(DISTINCT user_pseudo_id) AS cnt FROM funnel GROUP BY ALL ORDER BY event_date, step_number 연습문제 3: 일자별 각 퍼널의 유저 수 집계한 결과 → PIVOT 하기-- 퍼널 단계: 6 -- screen_view(welcome) -- screen_view(home) -- screen_view(food_category) -- screen_view(restaurant) -- screen_view(cart) -- click_payment(cart) WITH funnel AS ( SELECT event_date , CONCAT(event_name, '-', param.value.string_value) AS event_name_with_screen , CASE WHEN event_name = 'screen_view' AND param.value.string_value = 'welcome' THEN 1 WHEN event_name = 'screen_view' AND param.value.string_value = 'home' THEN 2 WHEN event_name = 'screen_view' AND param.value.string_value = 'food_category' THEN 3 WHEN event_name = 'screen_view' AND param.value.string_value = 'restaurant' THEN 4 WHEN event_name = 'screen_view' AND param.value.string_value = 'cart' THEN 5 WHEN event_name = 'click_payment' AND param.value.string_value = 'cart' THEN 6 END AS step_number , user_pseudo_id FROM `inflearn-bigquery-437203.advanced.app_logs` CROSS JOIN UNNEST(event_params) AS param WHERE event_date BETWEEN '2022-08-01' AND '2022-08-18' AND event_name IN ('screen_view', 'click_payment') AND param.key = 'firebase_screen' AND param.value.string_value IN ('welcome', 'home', 'food_category', 'restaurant', 'cart') ), -- 일자별 각 퍼널의 유저수 집계 funnel_daily AS( SELECT event_date , event_name_with_screen , MAX(step_number) AS step_number , COUNT(DISTINCT user_pseudo_id) AS cnt FROM funnel GROUP BY ALL ORDER BY event_date, step_number ) -- 일자별 각 퍼널의 유저수 집계 -> 피벗하기 SELECT event_date , SUM(IF(event_name_with_screen = 'screen_view-welcome', cnt, 0)) AS `screen_view-welcome` , SUM(IF(event_name_with_screen = 'screen_view-home', cnt, 0)) AS `scree_view-home` , SUM(IF(event_name_with_screen = 'screen_view-food_category', cnt, 0)) AS `screen_view-food_category` , SUM(IF(event_name_with_screen = 'screen_view-restaurant', cnt, 0)) AS `screen_view-restaurant` , SUM(IF(event_name_with_screen = 'screen_view-cart', cnt, 0)) AS `screen_view-cart` , SUM(IF(event_name_with_screen = 'click_payment-cart', cnt, 0)) AS `click_payment-cart` FROM funnel_daily GROUP BY event_date ORDER BY event_date 

[실습] 개인 프로젝트에서 많이 쓰는 CI/CD 구축 방법 - 2 에서 깃액션 배포할때 계속 이렇게 뜨는데 알려주세요 ㅠㅠㅠㅠㅠㅠㅠ 5번해봤는데 계속 저렇게뜹니다..

1-4. Array, Struct 연습문제 (1~4번)연습문제1문제array_exercises 테이블에서 각 영화(title)별로 장르(genres)를 UNNEST해서 보여주세요 쿼리select title, genres2 from advanced.array_exercises cross join unnest(genres) as genres2 ;결과 연습문제2문제array_exercises 테이블에서 각 영화(title)별로 배우(actor)와 배역(character)을 보여주세요. 배우와 배역은 별도의 컬럼으로 나와야 합니다쿼리select title, actor.actor, actor.character from advanced.array_exercises cross join unnest(actors) as actor order by movie_id ;결과 연습문제3문제array_exercises 테이블에서 각 영화(title)별로 배우(actor), 배역(character), 장르 (genre)를 출력하세요. 한 Row에 배우, 배역, 장르가 모두 표시되어야 합니다쿼리select title, actor.actor, actor.character genre2 # array<string> from advanced.array_exercises cross join unnest (actors) as actor cross join unnest (genres) as genre order by movie_id ;결과 연습문제4문제앱 로그 데이터(app_logs)의 배열을 풀어주세요쿼리select user_id, event_date, event_name, user_pseudo_id, event_param.key as key , event_param.value.string_value as string_value , event_param.value.int_value as int_value from advanced.app_logs cross join unnest (event_params) as event_param where event_date = "2022-08-01" limit 10 ;결과 1-9. 퍼널 SQL 쿼리 작성하기연습문제1문제orders 테이블에서 유저(user_id)별로 주문 금액(amount)의 합계를 PIVOT해주세요. 날짜(order_date)를 행(Row)으로, user_id를 열(Column)으로 만들어야 합니다쿼리select order_date, sum(if(user_id = 1, amount, 0)) as user_1, sum(if(user_id = 2, amount, 0)) as user_2, sum(if(user_id = 3, amount, 0)) as user_3 from advanced.orders group by order_date order by 1 ;결과연습문제2문제orders 테이블에서 날짜(order_date)별로 유저들의 주문 금액(amount)의 합계를 PIVOT 해주세요. user_id를 행(Row)으로, order_date를 열(Column)으로 만들어야 합니다쿼리select user_id, # 컬럼의 이름을 지정할때, 영어를 제외하고 backtick(`)사용 sum(if(order_date = "2023-05-01", amount, 0)) as `2023-05-01`, sum(if(order_date = "2023-05-02", amount, 0)) as `2023-05-02`, sum(if(order_date = "2023-05-03", amount, 0)) as `2023-05-03`, sum(if(order_date = "2023-05-04", amount, 0)) as `2023-05-04`, sum(if(order_date = "2023-05-05", amount, 0)) as `2023-05-05` from advanced.orders group by user_id order by 1 ;결과연습문제3문제orders 테이블에서 사용자(user_id)별, 날짜(order_date)별로 주문이 있다면 1, 없다면 0으로 PIVOT 해주세요. user_id를 행(Row)으로, order_date를 열(Column)로 만들고 주문을 많이 해도 1로 처리합니다쿼리select user_id, max(if(order_date = "2023-05-01", 1, 0)) as `2023-05-01`, max(if(order_date = "2023-05-02", 1, 0)) as `2023-05-02`, max(if(order_date = "2023-05-03", 1, 0)) as `2023-05-03`, max(if(order_date = "2023-05-04", 1, 0)) as `2023-05-04`, max(if(order_date = "2023-05-05", 1, 0)) as `2023-05-05` from advanced.orders group by user_id order by 1 ;결과연습문제4문제앱 로그 데이터 배열 PIVOT하기 - user_id = 32888이 카트 추가하기(click_cart)를 누를때 어떤 음식(food_id)을 담았나요?쿼리select event_date, event_timestamp, event_name, user_id, user_pseudo_id, max(if(param.key = 'firebase_screen', param.value.string_value, null)) as firebase_screen, -- max(if(param.key = 'food_id', param.value.string_value, null)) as food_id, max(if(param.key = 'food_id', param.value.int_value, null)) as food_id, max(if(param.key = 'session_id', param.value.string_value, null)) as session_id from advanced.app_logs cross join unnest(event_params) as param where event_date = "2022-08-01" and user_id = 32888 and event_name = "click_cart" group by all limit 100 ; 결과퍼널 분석문제step_number별 count, 일자별 퍼널별 유저 수 쿼리쿼리with base as (select event_date, event_timestamp, event_name, user_id, user_pseudo_id, max(if(event_param.key = 'firebase_screen', event_param.value.string_value, null)) as firebase_screen, -- max(if(event_param.key = 'food_id', event_param.value.int_value, null)) as food_id, max(if(event_param.key = 'session_id', event_param.value.string_value, null)) as session_id from advanced.app_logs cross join unnest(event_params) as event_param where 1=1 and event_date between "2022-08-01" and "2022-08-18" group by all ), filter_event_and_concat_event_and_acreen AS ( -- event_name + screen select * except(event_name, firebase_screen, event_timestamp), concat(event_name, "-", firebase_screen) as event_name_with_screen, datetime(timestamp_micros(event_timestamp), "Asia/Seoul") as event_datetime from base where 1=1 and event_name in ("screen_view", "click_payment")) # 일자별로 퍼널별 유저 수 select -- distinct(event_name_with_screen) event_date, event_name_with_screen, case when event_name_with_screen = 'screen_view-welcome' then 1 when event_name_with_screen = 'screen_view-home' then 2 when event_name_with_screen = 'screen_view-food_category' then 3 when event_name_with_screen = 'screen_view-restaurant' then 4 when event_name_with_screen = 'screen_view-cart' then 5 when event_name_with_screen = 'click_payment-cart' then 6 else null end as step_number, count(distinct user_pseudo_id) as cnt from filter_event_and_concat_event_and_acreen group by all having step_number is not null order by event_date ;결과    

강의에 사용되는 자료와 코드들은 어디서 받을 수 있나요?

1. ARRAY, STRUCT 연습문제 연습 문제 1번# 1)array_exercises테이블에서 각 영화(title)별로 장르(genres)를 UNNEST해서 보여주세요 SELECT title, genre FROM `advanced.array_exercises` AS exercise CROSS JOIN UNNEST(genres) AS genre SELECT title, # 기존에 array_exercises에 저장되어 있던 컬럼 genre FROM `advanced.array_exercises` AS ae, UNNEST(genres) AS genre # ARRAY : 같은 타입의 여러 데이터를 저장하고 싶을 때 # ARRAY를 Flatten(평면화) => UNNEST # UNNEST를 할 때는 CROSS JOIN + UNNEST(ARRAY_COLUMN) # UNNEST(ARRAY_COLUMN) AS 새로운 이름 # SELECT 절에서 새로운 이름으로 시작한다. 기존의 ARRAY_COLUMN은 사용하지 않는다! 연습 문제 2번# 2) array_exercises 테이블에서 각 영화(title)별로 배우(actor)와 배역(character)을 보여주세요. 배우와 배역은 별도의 컬럼으로 나와야 합니다 SELECT title, actor.actor, actor.character -- FROM `advanced.array_exercises` AS ae, UNNEST(actors) AS actor FROM `advanced.array_exercises` AS ae CROSS JOIN UNNEST(actors) AS actor # actors = [STRUCT(STRING, STRING)]  연습 문제 3번# 3) array_exercises 테이블에서 각 영화(title)별로 배우(actor), 배역(character), 장르(genre)를 출력하세요. 한 Row에 배우, 배역, 장르가 모두 표시 되어야 합니다 SELECT title, actor.actor, actor.character, genre FROM `advanced.array_exercises` AS ae ,UNNEST(actors) AS actor, UNNEST(genres) as genre -- FROM `advanced.array_exercises` AS ae -- CROSS JOIN UNNEST(actors) AS actor -- CROSS JOIN UNNEST(genres) as genre # 이 문제의 의도 : UNNEST를 2번 연속 사용할 수 있다. # CROSS JOIN => JOIN 연속 2번과 맥락은 동일한데, UNNEST라는 것이 어색할 수 있었다 # 데이터의 중복이 어느정도 생기는데, 그것은 어쩔 수 없는 이슈(CROSS JOIN) -- FROM `advanced.array_exercises` AS ae -- CROSS JOIN UNNEST(actors) AS actor, UNNEST(genres) as genre SELECT title, actor.actor, actor.character, genre FROM `advanced.array_exercises` AS ae ,UNNEST(actors) AS actor, UNNEST(genres) as genre -- FROM `advanced.array_exercises` AS ae -- CROSS JOIN UNNEST(actors) AS actor -- CROSS JOIN UNNEST(genres) as genre # 이 문제의 의도 : UNNEST를 2번 연속 사용할 수 있다. # CROSS JOIN => JOIN 연속 2번과 맥락은 동일한데, UNNEST라는 것이 어색할 수 있었다 # 데이터의 중복이 어느정도 생기는데, 그것은 어쩔 수 없는 이슈(CROSS JOIN) -- FROM `advanced.array_exercises` AS ae -- CROSS JOIN UNNEST(actors) AS actor, UNNEST(genres) as genre WHERE actor.actor = 'Chris Evans' AND genre = 'Action' -- WHERE actor = 'Chris Evans' (X) # 실행 순서 : FROM -> JOIN -> SELECT # actors : ARRAY<STRUCT> => UNNEST => STRUCT # genres : ARRAY<STRING> => STRING  연습 문제 4번# 4) 앱 로그 데이터(app_logs)의 배열을 풀어주세요 SELECT event_date, event_timestamp, event_name, event_param.key as key, event_param.value as value, event_param.value.string_value as string_value, event_param.value.int_value as int_value, -- event_params, user_id, event_param FROM `advanced.app_logs` CROSS JOIN UNNEST(event_params) AS event_param WHERE event_date ='2022-08-01'  2. PIVOTPIVOT 연습 문제 1## SubQuery 방식 SELECT order_date, SUM(IF(user_id = 1, sum_of_amount, NULL)) AS user_1, SUM(IF(user_id = 2, sum_of_amount, NULL)) AS user_2, SUM(IF(user_id = 3, sum_of_amount, NULL)) AS user_3 -- MAX를 써도 동일한 결과 값이 나옴 -- 그룹화 할때 값이 하나밖에 없음 FROM ( SELECT order_date, user_id, # Amount의 합 SUM(amount) AS sum_of_amount FROM advanced.orders GROUP BY order_date, user_id -- ORDER BY order_date ) GROUP BY order_date ORDER BY order_date  PIVOT 연습 문제 2# ANY_VALUE 활용 -- ANY_VALUE : 그룹화 할 대상 중에 임의의 값을 선택한다 (NULL)을 제외하고 -- ANY_VALUE에선 나머지 값들이 NULL 이거나 확정적으로 이 값이 나올 것이다 기대할 때 사용한다 SELECT user_id, ANY_VALUE(IF(order_date = PARSE_DATE('%Y-%m-%d', '2023-05-01'), amount, NULL)) AS `2023-05-01`, ANY_VALUE(IF(order_date = date('2023-05-02'), amount, NULL)) AS `2023-05-02`, ANY_VALUE(IF(order_date = date('2023-05-03'), amount, NULL)) AS `2023-05-03`, ANY_VALUE(IF(order_date = date('2023-05-04'), amount, NULL)) AS `2023-05-04`, ANY_VALUE(IF(order_date = date('2023-05-05'), amount, NULL)) AS `2023-05-05` FROM `advanced.orders` GROUP BY user_id ORDER BY user_id   PIVOT 연습 문제 3# 3) orders 테이블에서 사용자(user_id)별, 날짜(order_date)별로 주문이 있다면 1, 없다면 0으로 PIVOT 해주세요.user_id를 행(Row)으로, order_date를 열(Column)로 만들고 주문을 많이 해도 1로 처리합니다 SELECT user_id, # amount 대신 1 이라고 표시. IF 문 안에 TRUE 일 때의 값이 항상 특정 컬럼이 아니라 1이라고 할 수도 있음(유무에 따라서) MAX(IF(order_date = PARSE_DATE('%Y-%m-%d', '2023-05-01'), 1, 0)) AS `2023-05-01`, MAX(IF(order_date = date('2023-05-02'), 1, 0)) AS `2023-05-02`, MAX(IF(order_date = date('2023-05-03'), 1, 0)) AS `2023-05-03`, MAX(IF(order_date = date('2023-05-04'), 1, 0)) AS `2023-05-04`, MAX(IF(order_date = date('2023-05-05'), 1, 0)) AS `2023-05-05` FROM `advanced.orders` GROUP BY user_id  PIVOT 연습 문제 4 앱 로그 데이터 배열 PIVOT 하기WITH base AS ( SELECT event_date, event_name, user_id, user_pseudo_id, event_timestamp, MAX(IF(param.key = 'firebase_screen', param.value.string_value, NULL)) AS firebase_screen, MAX(IF(param.key = 'food_id', param.value.int_value, NULL)) AS food_id, MAX(IF(param.key = 'session_id', param.value.string_value, NULL)) AS session_id FROM `advanced.app_logs` CROSS JOIN UNNEST(event_params) AS param GROUP BY ALL -- WHERE event_name ='click_cart' ORDER BY user_pseudo_id LIMIT 100 ) SELECT event_date, COUNT(user_id) AS user_cnt FROM base WHERE event_name ='click_cart' GROUP BY event_date ORDER BY event_date   3. 퍼널 분석 -- event_name + screen (필요한 이벤트만 WHERE 조건에 걸어서 사용) -- step_number + COUNT WITH base AS ( SELECT event_date, event_timestamp, event_name, user_id, user_pseudo_id, platform, -- param MAX(IF(param.key = 'firebase_screen', param.value.string_value, NULL)) AS firebase_screen, MAX(IF(param.key = 'food_id', param.value.int_value, NULL)) AS food_id, MAX(IF(param.key = 'session_id', param.value.string_value, NULL)) AS session_id, FROM advanced.app_logs CROSS JOIN UNNEST(event_params) AS param WHERE event_date = '2022-08-01' GROUP BY ALL -- LIMIT 100 ), filter_event_and_concat_event_and_screen AS ( SELECT * EXCEPT(event_name, firebase_screen), CONCAT(event_name, "-", firebase_screen) AS event_name_with_screen FROM base WHERE event_name IN ("screen_view", "click_payment") ) SELECT * FROM filter_event_and_concat_event_and_screen  최종 RESULT# 일자 상관 없이 퍼널의 유저 수를 집계한 쿼리 => 일자별로 하기 위해 event_date 추가WITH base AS ( SELECT event_date, event_timestamp, event_name, user_id, user_pseudo_id, platform, -- param MAX(IF(param.key = 'firebase_screen', param.value.string_value, NULL)) AS firebase_screen, MAX(IF(param.key = 'session_id', param.value.string_value, NULL)) AS session_id, FROM advanced.app_logs CROSS JOIN UNNEST(event_params) AS param WHERE -- event_date = '2022-08-01' # 적은 데이터로 쿼리를 작성하기 위해 만들어둔 조건 event_date BETWEEN '2022-08-01' AND '2022-08-18' GROUP BY ALL ), filter_event_and_concat_event_and_screen AS ( SELECT * EXCEPT(event_name, firebase_screen), CONCAT(event_name, "-", firebase_screen) AS event_name_with_screen, DATETIME(TIMESTAMP_MICROS(event_timestamp), 'Asia/Seoul') AS event_datetime FROM base WHERE event_name IN ("screen_view", "click_payment") ) -- step_number + COUNT -- step_number : CASE WHEN 을 사용해 숫자 지정, 조건문을 여러 개 하고싶을 때 사용하는 함수 # 일자 상관 없이 퍼널의 유저 수를 집계한 쿼리 => 일자별로 하기 위해 event_date 추가 SELECT event_date, # 일자별로 퍼널별 유저 수 쿼리 event_name_with_screen, -- event_name_with_screen, -- event_datetime, user_pseudo_id, CASE WHEN event_name_with_screen = 'screen_view-welcome' THEN 1 WHEN event_name_with_screen = 'screen_view-home' THEN 2 WHEN event_name_with_screen = 'screen_view-food_category' THEN 3 WHEN event_name_with_screen = 'screen_view-restaurant' THEN 4 WHEN event_name_with_screen = 'screen_view-cart' THEN 5 WHEN event_name_with_screen = 'click_payment-cart' THEN 6 ELSE NULL END AS step_number, COUNT(DISTINCT user_pseudo_id) AS CNT FROM filter_event_and_concat_event_and_screen GROUP BY ALL HAVING step_number IS NOT NULL ORDER BY event_date   

안녕하세요, 오랜만에 흥미로운 강의를 알게되어 주말동안 강의를 몰아보다보니 9강까지 듣게 되었네요. 23분 59초 정도에 setter를 지양하기 떄문에 custom setter를 잘 사용하지 않고, update함수를 만들어 사용한다 라는 내용에 예시가 있다면 알 수 있을까요? java 프로젝트를 활용할 때 setter를 커스텀하게 수정해서 쓰는 경우가 아주 간혹 값이 업데이트 될 때 다른 필드를 함께 업데이트 해야하는 케이스들 때문에 사용했던 기억이 있는데, setter를 사용하지 않고 update를 사용한다는게 어떤 말씀이신지 조금 더 상세히 알려주시면 감사하겠습니다!

1. ARRAY, STRUCT1) array_exercises 테이블에서 각 영화(title)별로 장르(genres)를 UNNEST해서 보여주세요SELECT title, genre FROM advanced.array_exercises CROSS JOIN UNNEST(genres) AS genre2) array_exercises 테이블에서 각 영화(title)별로 배우(actor)와 배역(character)을 보여주세요. (배우와 배역은 별도의 컬럼으로 나와야 합니다)SELECT title, actor.actor, actor.character FROM advanced.array_exercises CROSS JOIN UNNEST(actors) AS actor3) array_exercises 테이블에서 각 영화(title)별로 배우(actor), 배역(character), 장르(genre)를 출력하세요. 한 Row에 배우, 배역, 장르가 모두 표시되어야 합니다SELECT title, actor.actor, actor.character, genre FROM advanced.array_exercises CROSS JOIN UNNEST(actors) AS actor CROSS JOIN UNNEST(genres) AS genre4) 앱 로그 데이터(app_logs)의 배열을 풀어주세요SELECT user_id, event_date, event_name, user_pseudo_id, event_param.key AS key, event_param.value.string_value AS string_value, event_param.value.int_value AS int_value FROM advanced.app_logs CROSS JOIN UNNEST(event_params) AS event_param WHERE event_date = '2022-08-01'2. PIVOT1) orders 테이블에서 유저(user_id)별로 주문 금액(amount)의 합계를 PIVOT해주세요. 날짜(order_date)를 행(Row)으로, user_id를 열(Column)으로 만들어야 합니다SELECT order_date, SUM(IF(user_id = 1, amount, 0)) AS user_1, SUM(IF(user_id = 2, amount, 0)) AS user_2, SUM(IF(user_id = 3, amount, 0)) AS user_3, FROM advanced.orders GROUP BY order_date ORDER BY order_date 2) orders 테이블에서 날짜(order_date)별로 유저들의 주문 금액(amount)의 합계를 PIVOT 해주세요. user_id를 행(Row)으로, order_date를 열(Column)으로 만들어야 합니다-- 2) orders 테이블에서 날짜(order_date)별로 유저들의 주문 금액(amount)의 합계를 PIVOT 해주세요. user_id를 행(Row)으로, order_date를 열(Column)으로 만들어야 합니다 SELECT user_id, SUM(IF(order_date = '2023-05-01', amount, 0)) AS `2023-05-01`, SUM(IF(order_date = '2023-05-02', amount, 0)) AS `2023-05-02`, SUM(IF(order_date = '2023-05-03', amount, 0)) AS `2023-05-03`, SUM(IF(order_date = '2023-05-04', amount, 0)) AS `2023-05-04`, SUM(IF(order_date = '2023-05-05', amount, 0)) AS `2023-05-05`, FROM advanced.orders GROUP BY user_id ORDER BY user_id3) orders 테이블에서 사용자(user_id)별, 날짜(order_date)별로 주문이 있다면 1, 없다면 0으로 PIVOT 해주세요. user_id를 행(Row)으로, order_date를 열(Column)로 만들고 주문을 많이 해도 1로 처리합니다SELECT user_id, MAX(IF(order_date = '2023-05-01', 1, 0)) AS `2023-05-01`, MAX(IF(order_date = '2023-05-02', 1, 0)) AS `2023-05-02`, MAX(IF(order_date = '2023-05-03', 1, 0)) AS `2023-05-03`, MAX(IF(order_date = '2023-05-04', 1, 0)) AS `2023-05-04`, MAX(IF(order_date = '2023-05-05', 1, 0)) AS `2023-05-05`, FROM advanced.orders GROUP BY user_id ORDER BY user_id4) 앱 로그 데이터 배열 PIVOT하기# 앱 로그 PIVOT # 쿼리를 작성하는 목표, 확인할 지표 : user_id = 32888이 카트 추가하기(click_cart)를 누를때 어떤 음식(food_id)을 담았나요? # 쿼리 계산 방법 : UNNEST -> PIVOT # 데이터의 기간 : X # 사용할 테이블 : app_logs # Join KEY : X # 데이터 특징: -- event_params ARRAY, STRUCT / event_params.value ARRAY, STRUCT WITH base AS ( SELECT user_id, event_date, event_name, user_pseudo_id, event_param.key AS key, event_param.value.string_value AS string_value, event_param.value.int_value AS int_value FROM advanced.app_logs CROSS JOIN UNNEST(event_params) AS event_param ) SELECT user_id, event_date, event_name, user_pseudo_id, MAX(IF(key = 'firebase_screen', string_value, NULL)) AS firebase_screen, MAX(IF(key = 'food_id', int_value, NULL)) AS food_id, MAX(IF(key = 'session_id', string_value, NULL)) AS session_id FROM base WHERE user_id = 32888 AND event_name = 'click_cart' GROUP BY ALL3. 퍼널WITH base AS ( SELECT event_date, event_timestamp, event_name, user_id, user_pseudo_id, platform, MAX(IF(event_param.key = 'firebase_screen', event_param.value.string_value, NULL)) AS firebase_screen, MAX(IF(event_param.key = 'session_id', event_param.value.string_value, NULL)) AS session_id FROM advanced.app_logs CROSS JOIN UNNEST(event_params) AS event_param WHERE event_date BETWEEN '2022-08-01' AND '2022-08-18' GROUP BY ALL ), filter_event_and_concat_event_and_screen AS ( SELECT * EXCEPT(event_name, firebase_screen, event_timestamp), CONCAT(event_name, "-", firebase_screen) AS event_name_with_screen, DATETIME(TIMESTAMP_MICROS(event_timestamp), 'Asia/Seoul') AS event_datetime FROM base WHERE event_name IN ('screen_view', 'click_payment') ), daily_event_summary AS ( SELECT event_date, # 일자별로 퍼널별 유저 수 쿼리 event_name_with_screen, CASE WHEN event_name_with_screen = 'screen_view-welcome' THEN 1 WHEN event_name_with_screen = 'screen_view-home' THEN 2 WHEN event_name_with_screen = 'screen_view-food_category' THEN 3 WHEN event_name_with_screen = 'screen_view-restaurant' THEN 4 WHEN event_name_with_screen = 'screen_view-cart' THEN 5 WHEN event_name_with_screen = 'click_payment-cart' THEN 6 ELSE NULL END AS step_number, COUNT(DISTINCT user_pseudo_id) AS cnt FROM filter_event_and_concat_event_and_screen GROUP BY ALL HAVING step_number IS NOT NULL ) -- 집계한 데이터 PIVOT SELECT event_date, MAX(IF(event_name_with_screen = 'screen_view-welcome', cnt, 0)) AS screen_view_welcome, MAX(IF(event_name_with_screen = 'screen_view-home', cnt, 0)) AS screen_view_home, MAX(IF(event_name_with_screen = 'screen_view-food_category', cnt, 0)) AS screen_view_food_category, MAX(IF(event_name_with_screen = 'screen_view-restaurant', cnt, 0)) AS screen_view_restaurant, MAX(IF(event_name_with_screen = 'screen_view-cart', cnt, 0)) AS screen_view_cart, MAX(IF(event_name_with_screen = 'click_payment-cart', cnt, 0)) AS click_payment_cart FROM daily_event_summary GROUP BY ALL ORDER BY event_date