총 정리 문제 풀이 2번 방출 여부 상관

감사합니다. 선생님, 저의 원래 질문 의도는 방출되지 않은(status IN("Active", "Training") 포켓몬의 type1, kor_name, 포켓몬의 수를 구하고 싶었습니다!선생님 말씀대로라면 아래 쿼리처럼 하면 될까요??WITH results_release_pokemon AS ( SELECT p.type1, tp.status, p.kor_name, COUNT(tp.id) AS cnt, CASE WHEN status IN("Active", "Training") THEN "no_released" ELSE "released" END AS result_release_pokemon FROM basic.trainer_pokemon AS tp LEFT JOIN basic.pokemon as p ON tp.pokemon_id = p.id GROUP BY p.type1, tp.status, p.kor_name ORDER BY cnt DESC ) SELECT type1, kor_name, cnt FROM results_release_pokemon AS rrp WHERE result_release_pokemon = "no_released"