안녕하세요.
수업잘 듣고 있습니다.^^
봉우리 문제에서 all()구문을 for문으로 짜보고 싶은데요..
*수업코드*
cnt=0
for i in range(1, n+1):
&nbsp; &nbsp; for j in range(1, n+1):
&nbsp; &nbsp; &nbsp; &nbsp; if all(a[i][j]&gt;a[i+dx[k]][j+dy[k]] for k in range(4)):
&nbsp; &nbsp; &nbsp; &nbsp; &nbsp; &nbsp; cnt+=1
print(cnt)&nbsp;
이 부분을
*제코드*&nbsp;&nbsp;
<div style="color: #d4d4d4; background-color: #1e1e1e; font-family: Consolas, 'Courier New', monospace; font-size: 18px; line-height: 24px; white-space: pre;">
<div>cnt=0</div>
<div>for&nbsp;i&nbsp;in&nbsp;range(1,n+1):</div>
<div>&nbsp;&nbsp;&nbsp;&nbsp;for&nbsp;j&nbsp;in&nbsp;range(1,n+1):</div>
<div>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;for&nbsp;k&nbsp;in&nbsp;range(4):</div>
<div>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;if&nbsp;b[i][j]&nbsp;&lt;&nbsp;b[i+dx[k]][j+dy[k]]:</div>
<div>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;break</div>
<div>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;else:</div>
<div>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;cnt+=1</div>
<div>&nbsp;&nbsp;&nbsp;&nbsp;</div>
<div>print(cnt)</div>
</div>
이렇게 바꾸어 봤는데 답이 틀려서 혹시 for 문으로 작성할 수 있나요?

안녕하세요^^
아래와 같이 하시면 될 것 같습니다.
b[i][j] &lt;=&nbsp;b[i+dx[k]][j+dy[k]]

인프런 커뮤니티 질문&답변

섹션 3 봉우리문제 질문이요!!