<div style="color: #eeffff; background-color: #212121; font-family: Consolas, 'Courier New', monospace; font-size: 10px; line-height: 14px; white-space: pre;">
<div>function&nbsp;solution(need,&nbsp;plan){</div>
<div>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;let&nbsp;answer&nbsp;=&nbsp;"YES";</div>
<div>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;let&nbsp;queue&nbsp;=&nbsp;need.split('');</div>
<div>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;for(let&nbsp;x&nbsp;of&nbsp;plan){</div>
<div>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;if(queue.includes(x)&nbsp;&amp;&amp;&nbsp;queue[0]&nbsp;===&nbsp;x)&nbsp;queue.shift();</div>
<div>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;}</div>
<div>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;if(queue.length&nbsp;!==&nbsp;0)&nbsp;answer&nbsp;=&nbsp;"NO";</div>
<div>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;return&nbsp;answer;</div>
<div>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;}</div>
</div>

안녕하세요^^
입력설명을 보면 수업설계의 길이가 30까지입니다. 즉 수업설계에서 같은 수업을 두 번듣게 설계할 수도 있다는 의미입니다.&nbsp;
아래와 같은 경우 "YES"가 나옵니다.

<div style="color: #f8f8f2; background-color: #272822; font-family: Consolas, 'Courier New', monospace; font-size: 20px; line-height: 27px; white-space: pre;">
<div>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;let&nbsp;a="ABC";</div>
<div>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;let&nbsp;b="BABC";</div>
<div>&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;console.log(solution(a,&nbsp;b));</div>
</div>

인프런 커뮤니티 질문&답변

이런 식의 풀이법은 맞는건가요?