안녕하세요 강사님! 질문있습니다.!

Question

강의 에서는 User 객체에 String roles를 만들고 PrincipalDetailse 객체의 getAuthorities함수에서 밑에 처럼 진행하였는데요 public PrincipalDetails(Customer customer) { this.customer = customer; } @Override public Collection getAuthorities() { Collection authorities = new ArrayList<>(); customer.getRoleList().forEach(r -> { authorities.add(() -> r); }); return authorities; } User객체의 Role role 필드를 추가하여 public enum Role { ROLE_CUSTOMER,ROLE_ADMIN,ROLE_SELLER } PrincipalDetailse 객체의 getAuthorities함수 적는방법이 도무지 생각나지 않아 질문드립니다 ㅠ 어떻게 해야할까요.. 도움 구하고싶습니다,

최주호 · Answer

package com.example.kakao.users; import javax.persistence.AttributeConverter; import javax.persistence.Converter; import java.util.Arrays; import java.util.Collections; import java.util.List; import java.util.stream.Collectors; @Converter public class StringArrayConverter implements AttributeConverter, String> { private static final String SPLIT_CHAR = ","; @Override public String convertToDatabaseColumn(List attribute) { return attribute.stream().map(String::valueOf).collect(Collectors.joining(SPLIT_CHAR)); } @Override public List convertToEntityAttribute(String dbData) { if(dbData == null) { // JPA save는 select부터 하기 때문에, null을 체크해줘야 한다. return Collections.emptyList(); } else { return Arrays.stream(dbData.split(SPLIT_CHAR)) .map(String::valueOf) .collect(Collectors.toList()); } } } package com.example.kakao.users; import lombok.*; import javax.persistence.*; import java.util.ArrayList; import java.util.List; @Getter @NoArgsConstructor(access = AccessLevel.PROTECTED) @Entity @Table(name="user_tb") public class User{ @Id @GeneratedValue(strategy = GenerationType.IDENTITY) private int id; private String email; // 인증시 필요한 필드 private String password; private String username; @Convert(converter = StringArrayConverter.class) private List roles = new ArrayList<>(); // role은 한 개 이상 @Builder public User(int id, String email, String password, String username, List roles) { this.id = id; this.email = email; this.password = password; this.username = username; this.roles = roles; } } package com.example.kakao._core.security; import com.example.kakao.users.User; import lombok.Getter; import lombok.RequiredArgsConstructor; import org.springframework.security.core.GrantedAuthority; import org.springframework.security.core.authority.SimpleGrantedAuthority; import org.springframework.security.core.userdetails.UserDetails; import java.util.Collection; import java.util.stream.Collectors; @RequiredArgsConstructor @Getter public class CustomUserDetails implements UserDetails { private final User user; @Override public Collection getAuthorities() { return this.user.getRoles().stream() .map(SimpleGrantedAuthority::new) .collect(Collectors.toList()); } @Override public String getPassword() { return user.getPassword(); } @Override public String getUsername() { return user.getEmail(); } @Override public boolean isAccountNonExpired() { return true; } @Override public boolean isAccountNonLocked() { return true; } @Override public boolean isCredentialsNonExpired() { return true; } @Override public boolean isEnabled() { return true; } }

qheogus55 · Answer

public enum Role { ROLE_CUSTOMER, ROLE_SELLER; } // public class Customer extends BaseTimeEntity { @Enumerated(EnumType.STRING) private Role role; } @Override public Collection getAuthorities() { Collection authorities = new ArrayList<>(); authorities.add(new GrantedAuthority() { @Override public String getAuthority() { return customer.getRole().toString(); } }); return authorities; } @Override public void signUpCustomer(CustomerSignUpDto customerSignUpDto) throws Exception { Customer customer = customerSignUpDto.toEntity(); customer.encodePassword(passwordEncoder); customer.addCustomerAuthority(); if (customerRepository.findByUsername(customer.getUsername()).isPresent()) { throw new Exception("이미 존재하는 아이디입니다."); } customerRepository.save(customer); } public void addSellerAuthority(){ this.role = Role.ROLE_SELLER; } 답변 매우감사드립니다!! 혹시 이 코드도 제대로 동작하는데 문제없을까요?..