인프런 커뮤니티 질문&답변

테스트 코드에서 Member와 Member1을 반영했다고 생각했는데

왜 Member만 DB에 반영되는지 모르겠습니다. ㅠㅠ

@SpringBootTest
class OrderServiceImplTest {


    @Autowired
    EntityManager em;

    ApplicationContext ac = new AnnotationConfigApplicationContext(AppConfig.class);
    
    MemberService memberService = ac.getBean(MemberService.class);
    
    
    @Test
    @Transactional
    @Rollback(false)
    public void testSaveMember(){
        Member member = new Member();
        member.setUsername("kin11");
        member.setAddress(new Address("1","2","3"));
        em.persist(member);



        Member member1 = new Member();
        member1.setUsername("kin");
        member1.setAddress(new Address("1","2","3"));
        memberService.join(member1);

    }
}

package com.example.spring.repository;

import com.example.spring.domain.Member;

import java.util.List;



public interface MemberRepository {



    Long save(Member member);


    Member findOne(Long id);


    List<Member> findAll();


    List<Member> findByName(String username);

}

- 학습 관련 질문을 남겨주세요. 상세히 작성하면 더 좋아요!

package com.example.spring.repository;


import com.example.spring.domain.Member;

import lombok.RequiredArgsConstructor;
import org.springframework.beans.factory.annotation.Autowired;

import org.springframework.stereotype.Repository;


import javax.persistence.EntityManager;
import javax.persistence.PersistenceContext;
import java.util.List;


@Repository
public class MemberRepositoryImpl implements MemberRepository {


    @PersistenceContext
    EntityManager em;

    

    @Override
    public Long save(Member member) {
        em.persist(member);
        return member.getId();
    }

    @Override
    public Member findOne(Long id) {
        return em.find(Member.class, id);
    }

    @Override
    public List<Member> findAll() {
        return em.createQuery("select m from Member m",Member.class).getResultList();

    }

    @Override
    public List<Member> findByName(String username) {
        return em.createQuery("select m from Member m where m.username =:name",Member.class)
                .setParameter("name",username )
                .getResultList();
    }
}

- 먼저 유사한 질문이 있었는지 검색해보세요.

package com.example.spring.service;

import com.example.spring.domain.Member;

import java.util.List;



public interface MemberService {

    Long join(Member member);

    List findMembers();

    Member findOne(Long Id);

}

package com.example.spring.service;

import com.example.spring.domain.Member;
import com.example.spring.repository.MemberRepository;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.stereotype.Service;
import org.springframework.transaction.annotation.Transactional;

import java.util.List;


@Service
@Transactional
public class MemberServiceImpl implements MemberService {


    private final MemberRepository memberRepository;

    @Autowired
    public MemberServiceImpl(MemberRepository memberRepository) {
        this.memberRepository = memberRepository;
    }

    //회원 등록
    @Override
    public Long join(Member member) {
        validateDuplicateMember(member);
        memberRepository.save(member);
        return member.getId();
    }

    private void validateDuplicateMember(Member member) {
        List<Member> findMembers = memberRepository.findByName(member.getUsername());
        if (!findMembers.isEmpty()){
            throw new IllegalStateException("이미 존재하는 회원입니다.");
        }

    }
    //회원 전체 조회
    @Override
    @Transactional(readOnly = true)
    public List findMembers() {
        return memberRepository.findAll();
    }


    //회원 한명 조회
    @Override
    @Transactional(readOnly = true)
    public Member findOne(Long Id){
        return  memberRepository.findOne(Id);
    }


}

package com.example.spring;


import org.springframework.context.annotation.ComponentScan;
import org.springframework.context.annotation.Configuration;

@Configuration
@ComponentScan
public class AppConfig {
}